Physics-
General
Easy

Question

In the figure, current through the 3 capital omega resistor is 0.8 ampere, then potential drop through 4 capital omega resistor is

  1. 9.6 V    
  2. 2.6 V    
  3. 4.8 V    
  4. 1.2 V    

The correct answer is: 4.8 V


    Current through 6W resistance in parallel with 3W resistance = 0.4 A
    So total current = 0.8 + 0.4 = 1.2 A
    Potential drop across 4 capital omega equals 1.2 cross times 4 equals 4.8 V

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