Physics-
General
Easy

Question

In the graph given below. If the slope is 4.12 cross times 1 0 to the power of negative 15 end exponentV-sec, then value of ‘h’ should be

  1. 6.6 cross times 1 0 to the power of negative 31 end exponent J-sec    
  2. 6.6 cross times 1 0 to the power of negative 34 end exponentJ-sec    
  3. 9.1 cross times 10 minus 31 J-sec    
  4. None of these    

The correct answer is: 6.6 cross times 1 0 to the power of negative 34 end exponentJ-sec


    Slope of V subscript 0 end subscript minus nu curve equals fraction numerator h over denominator e end fraction
    Þ h = Slope ´ e = 1.6 ´ 10–19´ 4.12 ´ 10–15
    equals 6.6 cross times 1 0 to the power of negative 34 end exponent J minus s e c.

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