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Physics

Fluid-Mechanics

Easy

Question

In the previous case, if water level is upto the edge of the gate as shown. horizontal and vertical thrust forces due to water on the gate will be

$\frac{π R^{2} d g L}{2}, 2 d g R^{2} L$
$2 d g R^{2} L, \frac{π R^{2} d g L}{2}$
$π R^{2} d g L, d g R^{2} L$
$d g R^{2} L, \frac{π R^{2} d g L}{2}$

The correct answer is: $2 d g R squared L comma fraction numerator pi R squared d g L over denominator 2 end fraction$

$text Net horizontal thrust is end text F equals open parentheses fraction numerator 0 plus d g 2 R over denominator 2 end fraction close parentheses 2 R L equals 2 d g R squared L text vertical thrust force is end text V d g equals fraction numerator pi R squared d g L over denominator 2 end fraction$

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