Physics-
General
Easy

Question

In the Wheatstone's bridge shown, P equals 2 capital omega comma Q equals 3 capital omega comma R equals 6 capital omega and S equals 8 capital omega. In order to obtain balance, shunt resistance across 'S' must be

  1. 2 capital omega    
  2. 3 capital omega    
  3. 6 capital omega    
  4. 8 capital omega    

The correct answer is: 8 capital omega


    Let the value of shunt be r. Hence the equivalent resistance of branch containing S will be fraction numerator S r over denominator S plus r end fraction
    In balance condition, fraction numerator P over denominator Q end fraction equals fraction numerator S r divided by left parenthesis S plus r right parenthesis over denominator R end fraction. This givesr equals 8 capital omega

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