Physics-
General
Easy

Question

Let[0] denote the dimensional formula of the permittivity of the vacuum, and [µ0] that of the permitivityof the vacuum. If M = mass, L = length, T = time and I = electric current,

  1. [0] = [M–1L–3T2 I]  
  2. [0] = [M–1LT4 I2]  
  3. 0] = [M LT–2 I–2]  
  4. 0] = [M L2 T–1 I]  

The correct answer is: [µ0] = [M LT–2 I–2]

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