Physics-
General
Easy

Question

Portion AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without slipping from A to B. If AB = BC, then ratio of translational kinetic energy to rotational kinetic energy, when the cylinder reaches point C is –

  1. 3/5  
  2. 5  
  3. 7/5  
  4. 8/3  

The correct answer is: 5


    K = KT
    or KT + KR = KT
    KR = (– 1)KT  KR = fraction numerator 1 over denominator 2 end fraction KT
    At point B : KT + KR = mg × h
     KR = fraction numerator m g h over denominator 3 end fraction
    At point C : KT + fraction numerator m g h over denominator 3 end fraction = mg × 2h
    KT = fraction numerator 5 m g h over denominator 3 end fraction
    fraction numerator K subscript T end subscript over denominator K subscript R end subscript end fraction = 5

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