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Physics-

General

Easy

Question

The area in the first quadrant enclosed by the axis, the line $x equals y square root of 3$ and the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4$ (greater area) is

$\frac{π}{2}$
$\frac{π}{3}$
$\frac{π}{4}$
$\frac{π}{6}$

The correct answer is: $fraction numerator pi over denominator 3 end fraction$

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