Physics-
General
Easy

Question

The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2 mu F. The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is

  1. 11.2 mu F    
  2. 15.6 mu F    
  3. 19.2 mu F    
  4. 22.4 mu F    

The correct answer is: 11.2 mu F


    C equals fraction numerator epsilon subscript 0 end subscript K A over denominator d end fraction Þ fraction numerator C subscript 1 end subscript over denominator C subscript 2 end subscript end fraction equals fraction numerator K subscript 1 end subscript over denominator K subscript 2 end subscript end fraction cross times fraction numerator d subscript 2 end subscript over denominator d subscript 1 end subscript end fraction
    fraction numerator 2 over denominator C subscript 2 end subscript end fraction equals fraction numerator 1 over denominator 2.8 end fraction cross times fraction numerator left parenthesis 0.4 divided by 2 right parenthesis over denominator left parenthesis 0.4 right parenthesis end fraction Þ C subscript 2 end subscript equals 11.2 mu F

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