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General
Easy

Question

The current through a 4.6 H inductor is shown in the following graph. The induced emf during the time interval t = 5 milli-sec to 6 milli-sec will be

  1. 103 V    
  2. – 23 cross times103 V    
  3. 23 cross times 103 V    
  4. Zero    

The correct answer is: 23 cross times 103 V


    Rate of decay of current between t = 5 ms to 6 ms equals fraction numerator d i over denominator d t end fraction equals negative left parenthesis text Slope of the line  end text B C right parenthesis
    equals negative open parentheses fraction numerator 5 over denominator 1 cross times 1 0 to the power of negative 3 end exponent end fraction close parentheses equals negative 5 cross times fraction numerator 1 0 to the power of 3 end exponent A over denominator s end fraction. Hence induced emf e equals negative L fraction numerator d i over denominator d t end fraction equals negative 4.6 cross times open parentheses negative 5 cross times 1 0 to the power of 3 end exponent close parentheses equals 23 cross times 1 0 to the power of 3 end exponent V

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