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Physics-

General

Easy

Question

The energy stored in an inductor of self inductance $L$ henry carrying a current of 1 A is

$L^{2} I$
$- L I^{2}$
$\frac{1}{2} L I^{2}$
$\frac{1}{2} L^{2} I$

The correct answer is: $fraction numerator 1 over denominator 2 end fraction L I to the power of 2 end exponent$

The energy stored in an inductor
$U equals fraction numerator 1 over denominator 2 end fraction L I to the power of 2 end exponent$

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