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Question

The horizontal component of the earth’s magnetic field at a place is 3 cross times 10 to the power of negative 4 end exponent blank T and the dip is tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 4 over denominator 3 end fraction close parentheses. A metal rod of length 0.25 blank m placed in the north-south position and is moved at a constant speed of 10 blank c m divided by s towards the east. The emf induced in the rod will be

  1. Zero  
  2. 1 blank mu V  
  3. 5 blank mu V3  
  4. 10 blank mu V  

The correct answer is: 10 blank mu V


    Rod is moving towards east, so induced emf across it’s end will be e equals B subscript V end subscript v l equals open parentheses B subscript H end subscript tan invisible function application ϕ close parentheses v l
    therefore e equals 3 cross times 10 to the power of negative 4 end exponent cross times fraction numerator 4 over denominator 3 end fraction cross times open parentheses 10 cross times 10 to the power of negative 2 end exponent close parentheses cross times 0.25 equals 10 to the power of negative 5 end exponent V equals 10 mu V

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