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Physics

Fluid-Mechanics

Easy

Question

The velocity of water in a river is $2 m s to the power of negative 1 end exponent$ at the surface. If the river is 2 m deep, the shearing stress between the horizontal layers of water assuming bottom layer at rest
( $eta equals 10 to the power of negative 3 end exponent P l$ for water)

$10^{- 2} N m^{- 2}$
$10^{- 3} N m^{- 2}$
$10^{- 1} N m^{- 2}$
$10 {Nm}^{- 2}$

The correct answer is: $10 to the power of negative 3 end exponent N m to the power of negative 2 end exponent$

$F over A equals eta fraction numerator d v over denominator d x end fraction equals 10 to the power of negative 3 end exponent cross times 2 over 2 equals 10 to the power of negative 3 end exponent Nm to the power of negative 2 end exponent$

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