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Physics-

General

Easy

Question

Two blocks $A$ and $B$ of masses 6 kg and 3 kg rest on a smooth horizontal surface as shown in the figure. If coefficient of friction between $A$ and $B$ is 0.4, the maximum horizontal force which can make them move without separation is
<img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/965253/1/1211142/Picture63.png" alt=""

72 N
40 N
36 N
20 N

hint Hint:

F=(ma+mb)a

The correct answer is: 36 N

Maximum frictional force on block $B$ is
$mu m subscript B end subscript g equals 0.4 cross times 3 cross times 10 equals 12$ N
Hence, maximum acceleration $equals fraction numerator 12 over denominator 3 end fraction equals 4 blank m s to the power of negative 1 end exponent$
Hence, maximum force
$F equals open parentheses m subscript A end subscript plus m subscript B end subscript close parentheses a equals open parentheses 6 plus 3 close parentheses cross times 4 equals 36$ N
Aliter: We can also apply the formula discussed in previous problem by putting $mu subscript 2 end subscript equals 0$ and $mu subscript 1 end subscript equals 0.4$

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