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Physics

Mechanics

Easy

Question

$text Two blocks of masses m end text subscript text 1 end text end subscript text and m end text subscript text 2 end text end subscript text are connected by a spring of spring constant k. end text text The block of mass m end text subscript text 2 end text end subscript text is given a sharp impulse so that it acquires a velocity v end text subscript text 0 end text end subscript text toward right end text text Find maximum elongation of spring end text$

$v_{0} {[\frac{m_{1} m_{2}}{(m_{1} + m_{2}) k}]}^{\frac{1}{2}}$
$v_{0} {(\frac{m_{1}^{2}}{(m_{1} + m_{2}) k})}^{\frac{1}{2}}$
$v_{0} [\frac{m_{2}^{2}}{(m_{1} + m_{2}) k}]$
$d a t a i n s u f f i c i e n t$

The correct answer is: $v subscript 0 open square brackets fraction numerator m subscript 1 m subscript 2 over denominator open parentheses m subscript 1 plus m subscript 2 close parentheses k end fraction close square brackets to the power of 1 half end exponent$

$S p r i n g space w i l l space b e space i n space m a x i m u m space e l o n g a t i o n space c o n d i t i o n space w h e n space b o t h space b l o c k space h a v e space s a m e space v e l o c i t y. space F r o m space m o m e n t u m space c o n s e r v a t i o n space space space m subscript 2 v subscript 0 equals open parentheses m subscript 1 plus m subscript 2 close parentheses v subscript e v subscript 0 superscript 2 open parentheses fraction numerator m subscript 1 m subscript 2 over denominator m subscript 1 plus m subscript 2 end fraction close parentheses equals k x squared comma space of 1em x equals v subscript 0 open square brackets k open parentheses fraction numerator m subscript 1 m subscript 2 over denominator m subscript 1 plus m subscript 2 end fraction close parentheses close square brackets to the power of 1 half end exponent$

Related Questions to study

$1. T w o space b l o c k s space o f space m a s s e s space m subscript 1 space a n d space m subscript 2 space a r e space space c o n n e c t e d space b y space a space s p r i n g space o f space s p r i n g space c o n s tan t space k. space T h e space b l o c k space o f space m a s s space m subscript 2 space i s space g i v e n space a space s h a r p space i m p u l s e space s o space t h a t space i t space a c q u i r e s space a space v e l o c i t y space v subscript 0 space t o w a r d space r i g h t. space space space V e l o c i t y space o f space c e n t r e space o f space m a s s space w i l l space b e space space$

$1. T w o space b l o c k s space o f space m a s s e s space m subscript 1 space a n d space m subscript 2 space a r e space space c o n n e c t e d space b y space a space s p r i n g space o f space s p r i n g space c o n s tan t space k. space T h e space b l o c k space o f space m a s s space m subscript 2 space i s space g i v e n space a space s h a r p space i m p u l s e space s o space t h a t space i t space a c q u i r e s space a space v e l o c i t y space v subscript 0 space t o w a r d space r i g h t. space space space V e l o c i t y space o f space c e n t r e space o f space m a s s space w i l l space b e space space$

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PhysicsMechanics

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PhysicsMechanics

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A projectile of mass m is thrown with velocity v making an angle of 30° with vertical. Neglecting air resistance the magnitude of change in momentum between the starting point and at the maximum height is

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PhysicsMechanics

Particle A makes a perfectly elastic head-on collision with another stationary particle B. They fly apart in opposite directions with equal velocities. Ratio of their masses $M subscript A over M subscript B$ will be

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PhysicsMechanics

parallel

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