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Question

Two bodies being a free fall from rest, from the same height 2s apart. How long after the first body begins to fall the two bodies will be 40m apart? (Take g equals 10 m s to the power of negative 2 end exponent)

  1. 1 s  
  2. 2 s  
  3. 3 s  
  4. 4 s  

The correct answer is: 3 s


    fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent minus fraction numerator 1 over denominator 2 end fraction g open parentheses t minus 2 close parentheses to the power of 2 end exponent equals 40
    or fraction numerator 1 over denominator 2 end fraction cross times 10 open parentheses 2 t minus 2 close parentheses open parentheses 2 close parentheses equals 40 or 2 t minus 2 equals 4 or t equals 3s

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