Physics
Grade-10
Easy
Question
Two bodies of equal masses 'm' kg, separated by 'r' meters are attracted by a gravitational force F. Suppose the mass of a body is doubled and their distance of separation is tripled. What will be the ratio of their initial and final force of attraction?
- 9: 2
- 2: 9
- 2: 3
- 3: 2
Hint:
Use the formula of force.
The correct answer is: 9: 2
The correct option is a)9: 2.
Force =
Here, G is gravitational constant, M is mass of one object, m is mass of another object and r is the distance between them.
F initial = Gm2/ R2
Now when we double the mass of an object and tripled the distance then the formula will be:
F final=
F initial : F final = 9:2
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