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Physics-

General

Easy

Question

Two capacitors of $3 p F$ and $6 p F$ are connected in series and a potential difference of $5000 blank V$ is applied across the combination. They are then disconnected and reconnected in parallel. The potential between the plates is

$2250 V$
$2222 V$
$2.25 \times 10^{6} V$
$1.1 \times 10^{6} V$

The correct answer is: $2222 V$

$fraction numerator 1 over denominator C end fraction equals fraction numerator 1 over denominator 3 end fraction plus fraction numerator 1 over denominator 6 end fraction rightwards double arrow C equals 2 blank p F$
Total charge $equals 2 cross times 10 to the power of negative 12 end exponent cross times 5000 equals 10 to the power of negative 8 end exponent C$
The new potential when the capacitors are connected in parallel is
$V equals fraction numerator 2 cross times 10 to the power of negative 8 end exponent over denominator left parenthesis 3 plus 6 right parenthesis cross times 10 to the power of negative 12 end exponent end fraction equals 2222 blank V$

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