Physics-
General
Easy

Question

Two particles A and B, each of mass m, are inter-connected by an inextensible such that the particle B hangs below a table as shown in the figure and particle A is on a rough rotating disc at a distance r from the axis of rotation of the disc. If the angular speed of the dis is omega equals square root of g divided by r end root, the frictional force developed at the interface of the particle & the disc is equal to

  1. mg/2    
  2. < mg/2    
  3. mg/square root of 2    
  4. zero    

The correct answer is: zero


    The particle of mass m experiences two forces (i) tension T (ii) frictional force f.
    Þ Since the particle A is rotating in a circular path of radius r, its centripetal acceleration,

    Þ r w2 = fraction numerator T minus f over denominator m end fraction
    Putting T = mg for equilibrium of the mass B & w2 = g/r
    we obtain f = mg – mr g/r = 0

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