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Physics

Mechanics

Easy

Question

Two rings of the same radius R and mass M are placed such that their centres coincide and their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the common centre and perpendicular to the plane of one of the rings is

$\frac{M R^{2}}{2}$
$M R^{2}$
$\frac{3 M R^{2}}{2}$
$2 M R^{2}$

The correct answer is: $fraction numerator 3 M R squared over denominator 2 end fraction$

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