Physics-
General
Easy

Question

A man measures the period of a simple pendulum inside a stationary lift ad finds it to be T second. If the lift accelerates upwards with an acceleration g/4, then the period of pendulum will be

  1. 2 T square root of 5
  2. T
  3. fraction numerator 2 T over denominator square root of 5 end fraction
  4. T over 4

The correct answer is: fraction numerator 2 T over denominator square root of 5 end fraction


    T equals 2 pi square root of l over g end root When lift is accelerated upwards with acceleration. a left parenthesis equals straight g divided by 4 right parenthesis Then effective acceleration due to gravity inside the lift
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell g subscript 1 equals g plus a equals g plus g over 4 equals fraction numerator 5 g over denominator 4 end fraction end cell row cell therefore T subscript 1 equals 2 pi square root of fraction numerator l over denominator 5 g divided by 4 end fraction end root equals 2 pi square root of l over g end root cross times fraction numerator 2 over denominator square root of 5 end fraction equals fraction numerator 2 T over denominator square root of 5 end fraction end cell end table

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