Maths-
General
Easy

Question

A poster has an area of 432 square inches. The length , in inches, of the poster is 6 inches longer than the width of the poster. Which of the following equations can be solved to determine the length, in inches, of the poster?

  1. x squared minus 6 equals 432
  2. x squared minus 6 x equals 432
  3. x squared plus 6 equals 432
  4. x squared plus 6 x equals 432

hintHint:

Hint:
We consider that the poster is a rectangle which has an area of 432 square inches. The area of a rectangle is given by length*breadth. In the question, we are given a relation between the length and the breadth of the rectangle. So we just need to use that and use it in the formula of finding the area to get an equation.

The correct answer is: x squared minus 6 x equals 432


    Given,
    Area of the poster = 432 square inches
    According to the question,
    Length of the poster is 6 inches longer than the breadth. Writing this
    statement in the mathematical form, we have
    Breadth of the poster
    equals left parenthesis x minus 6 right parenthesis text  inches  end text
    The poster is in the shape of a rectangle.
    We know,
    Area of a rectangle = Length text  × end text Breadth
    Thus,
    Area of the poster =x cross times left parenthesis x minus 6 right parenthesis
    432 equals x cross times left parenthesis x minus 6 right parenthesis
    Rewriting the above equation, we have
    x left parenthesis x minus 6 right parenthesis equals 432
    Simplifying, we get
    x squared minus 6 x equals 432
    The solution of the above equation gives the value of x , which is the length of the poster.
    Hence, the correct option is B)

    Note:
    The question can be further extended and ask us to find the length, breadth, or the perimeter of the poster. In that case, first we would solve the above equation to find the length of the poster and then use it to find the breadth. Finally we can find the perimeter easily by using the formula: perimeter equals 2 to the power of cross times(length + breadth).

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