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General
Easy

Question

A Submarine descends to 1 over 6 of its maximum depth. Then it descends another  2 over 3of
its maximum depth. If it now at 650 feet below sea level , What is its maximum depth

hintHint:

Form the equation using the given information.
○  Take variable quantities as x.

The correct answer is: Hence, the maximum depth is 780 feet.


    Answer
    •            Step-by-step explanation:
    ○   Given:
    First submarine descends to 1 over 6 of its maximum depth.
    Then it descends another   2 over 3of its maximum depth.
    The height below sea level is 650 feet.
    ○    Step 1:
    Let the maximum depth be x feet.
    So,
    At first, submarine descends  = 1 over 6 x feet.
    Then, submarine descends = 2 over 3 x feet.
    Total descend = 1 over 6 x + 2 over 3 x feet
    Total descend = 1 over 6 x  + 4 over 6 x feet
    Total descend = 5 over 6 x feet
    It is given that, height below sea level; is 650 feet
    5 over 6 x = 650

                   rightwards double arrow 5x =  650 × 6

                   rightwards double arrow 5x = 3900

                   rightwards double arrow x = 3900 over 5

                   rightwards double arrow x = 780

    • Final Answer:
                    Hence, the maximum depth is 780 feet.
     

    Depth is the actual distance of an object beneath the surface, as measured by submerging it with a perfect ruler. The depth of an object in a denser medium as seen from a rarer medium is referred to as apparent depth in a medium. Its value is less than the true depth.
     
    A formula for calculating ocean depth. D = V divided by 1/2 T D stands for depth (in meters) T= Time (in seconds) V = 1507 m/s (speed of sound in water) (speed of sound in water) 
     
    Since the speed of sound in water is known, the depth "d" is determined using the straightforward equation "d/2 = vt."

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