Maths-
General
Easy
Question
AB and DC are parallel sides of trapezium ABCD and ∠ADC= 90o. Given AB= 15 cm, CD = 40 cm and the diagonal AC= 41 cm. Calculate the area of the trapezium ABCD?
Hint:
Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
The correct answer is: Hence, the area of the trapezium ABCD is 247.5 cm2.
Applying Pythagoras theorem in △ADC
AC2 = AD2 + CD2
AD2 = 412 - 402
AD2 = 81
AD = 9 cm
Final Answer:
Hence, the area of the trapezium ABCD is 247.5 cm2.
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