At what distance from the center of earth, the value of acceleration due to gravity g will be half that of the surfaces  (R=Radius of earth)

Weight of a body is maximum at

At what height over the earth's pole, the free fall acceleration decreases by one percent .=km(Re=6400 km)

The length of the subtangent (if exists) at any point θ on the ellipse  is

The radii of two planets are respectively R₁ and R₂ and their densities are respectively  and  the ratio of the accelerations due to gravity at their surface is……

A body weight 500 N on the surface of the earth. How much would it weight half way below the surface of earth

Following two isomers are
–

Number of optically active isomers of tartaric acid is
–

The number of optically active isomers possible for - is -

It has chiral centre (*). It is-

Let g be the acceleration due to gravity at earth's surface and k be the rotational K.E of earth suppose the earth's radius decreases by 2% keeping alt other quantities same then

Optically active isomers but not mirror images are called -

The sum of the subtangent and subnormal to the curve  at  is

For such questions, we should know the formula of subtangent and subnormal

Which is a pair of geometrical isomers ?

are-

Assuming earth to be a sphere of a uniform density, what is value of gravitational acceleration. in mine 100 km below the earth surface .... ms^-2