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Chemistry-

General

Easy

Question

Based on the third law of thermodynamics; the entropy can be obtained using the equation

$Δ S = \frac{Δ H}{T}$
$\int_{0}^{T} T \cdot C_{p}^{- 1} d T = S$
$ΔG = TΔS$

$\int_{0}^{T} C_{p} T^{- 1} d T = S$

The correct answer is: $stretchy integral subscript 0 end subscript superscript T end superscript C subscript p end subscript T to the power of negative 1 end exponent d T equals S$

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