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Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as

Perkin’s reaction
Cannizzaro’s reaction
Sandmeyer’s reaction
Claisen condensation

The correct answer is: Cannizzaro’s reaction

Benzaldehyde on treatment with 50% aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like $H C H O$ (no $alpha$ -hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively.

The following reagent converts $C subscript 6 end subscript H subscript 5 end subscript C O C H O$ to $C subscript 6 end subscript H subscript 5 end subscript C H O H C O O N a$

chemistry-General

General

chemistry-

Benzaldehyde $plus N a O H rightwards arrow$

chemistry-General

General

chemistry-

Acetaldehyde cannot show

chemistry-General

General

Chemistry-

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at $5 minus 1 0 to the power of o end exponent C$

Chemistry-General

General

chemistry-

Which of the following will undergo aldol condensation

chemistry-General

General

chemistry-

$C subscript 2 end subscript H subscript 5 end subscript C H O$ and $left parenthesis C H subscript 3 end subscript right parenthesis subscript 2 end subscript C O$ can be distinguished by testing with

chemistry-General

General

chemistry-

Acetaldehyde when treated with dilute NaOH gives

chemistry-General

General

chemistry-

Which of the following compound will undergo self aldol condensation in the presence of cold dilute alkali

chemistry-General

General

chemistry-

Which of the following compounds containing carbonyl group will give coloured crystalline compound with

chemistry-General

General

maths-

If $cosh to the power of negative 1 end exponent invisible function application left parenthesis p plus i q right parenthesis equals u plus i v comma$ then the equation with roots $cos to the power of 2 end exponent invisible function application u$ and $cos h to the power of 2 end exponent invisible function application v$

maths-General

General

maths-

If $u equals logtan invisible function application open parentheses fraction numerator pi over denominator 4 end fraction plus fraction numerator x over denominator 2 end fraction close parentheses comma$ then $cos h u$ is equal to

maths-General

General

Maths-

If $k less or equal than sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x plus tan to the power of negative 1 end exponent invisible function application x less or equal than K$ , then

In this question, we have to find the range of function from k to K. Here we know that sin^-1x + cos^-1x = $straight pi over 2$ and it only defines if -1 ≤ x ≤ 1 . And tan^-1x lines in ( $fraction numerator negative straight pi over denominator 4 end fraction$ ) to ( $straight pi over 4$ ) .

If $k less or equal than sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x plus tan to the power of negative 1 end exponent invisible function application x less or equal than K$ , then

Maths-General

General

physics-

In an experiment with a beam balance an unknown mass m is balanced by two known masses of 16 kg and 4 kg as shown in figure. The value of the unknown mass m is :–

physics-General

General

physics-

A particle starts from the point (0m, 8m) and moves with uniform velocity of $3 stack i with tilde on top$ m/s After 5 seconds, the angular velocity of the particle about the origin will be

physics-General

General

physics-

A particle of mass M is at a distance a from surface of a thin spherical shell of equal mass and having radius a

physics-General

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Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as

Perkin’s reaction Cannizzaro’s reaction Sandmeyer’s reaction Claisen condensation

The correct answer is: Cannizzaro’s reaction

Benzaldehyde on treatment with 50% aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like (no -hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively.

Related Questions to study

The following reagent converts to

The following reagent converts to

Benzaldehyde

Benzaldehyde

Acetaldehyde cannot show

Acetaldehyde cannot show

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at

Which of the following will undergo aldol condensation

Which of the following will undergo aldol condensation

and can be distinguished by testing with

and can be distinguished by testing with

Acetaldehyde when treated with dilute NaOH gives

Acetaldehyde when treated with dilute NaOH gives

Which of the following compound will undergo self aldol condensation in the presence of cold dilute alkali

Which of the following compound will undergo self aldol condensation in the presence of cold dilute alkali

Which of the following compounds containing carbonyl group will give coloured crystalline compound with

Which of the following compounds containing carbonyl group will give coloured crystalline compound with

If then the equation with roots and

If then the equation with roots and

If then is equal to

If then is equal to

If , then

If , then

In an experiment with a beam balance an unknown mass m is balanced by two known masses of 16 kg and 4 kg as shown in figure. The value of the unknown mass m is :–

In an experiment with a beam balance an unknown mass m is balanced by two known masses of 16 kg and 4 kg as shown in figure. The value of the unknown mass m is :–

A particle starts from the point (0m, 8m) and moves with uniform velocity of m/s After 5 seconds, the angular velocity of the particle about the origin will be

A particle starts from the point (0m, 8m) and moves with uniform velocity of m/s After 5 seconds, the angular velocity of the particle about the origin will be

A particle of mass M is at a distance a from surface of a thin spherical shell of equal mass and having radius a

A particle of mass M is at a distance a from surface of a thin spherical shell of equal mass and having radius a

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Perkin’s reaction
Cannizzaro’s reaction
Sandmeyer’s reaction
Claisen condensation

Benzaldehyde on treatment with 50% aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like $H C H O$ (no $alpha$ -hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively.

The following reagent converts $C subscript 6 end subscript H subscript 5 end subscript C O C H O$ to $C subscript 6 end subscript H subscript 5 end subscript C H O H C O O N a$

The following reagent converts $C subscript 6 end subscript H subscript 5 end subscript C O C H O$ to $C subscript 6 end subscript H subscript 5 end subscript C H O H C O O N a$

Benzaldehyde $plus N a O H rightwards arrow$

Benzaldehyde $plus N a O H rightwards arrow$

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at $5 minus 1 0 to the power of o end exponent C$

Which of the following oxidation reactions can be carried out with chromic acid in aqueous acetone at $5 minus 1 0 to the power of o end exponent C$

$C subscript 2 end subscript H subscript 5 end subscript C H O$ and $left parenthesis C H subscript 3 end subscript right parenthesis subscript 2 end subscript C O$ can be distinguished by testing with

$C subscript 2 end subscript H subscript 5 end subscript C H O$ and $left parenthesis C H subscript 3 end subscript right parenthesis subscript 2 end subscript C O$ can be distinguished by testing with

If $u equals logtan invisible function application open parentheses fraction numerator pi over denominator 4 end fraction plus fraction numerator x over denominator 2 end fraction close parentheses comma$ then $cos h u$ is equal to

If $u equals logtan invisible function application open parentheses fraction numerator pi over denominator 4 end fraction plus fraction numerator x over denominator 2 end fraction close parentheses comma$ then $cos h u$ is equal to

If $k less or equal than sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x plus tan to the power of negative 1 end exponent invisible function application x less or equal than K$ , then

If $k less or equal than sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x plus tan to the power of negative 1 end exponent invisible function application x less or equal than K$ , then

A particle starts from the point (0m, 8m) and moves with uniform velocity of $3 stack i with tilde on top$ m/s After 5 seconds, the angular velocity of the particle about the origin will be

A particle starts from the point (0m, 8m) and moves with uniform velocity of $3 stack i with tilde on top$ m/s After 5 seconds, the angular velocity of the particle about the origin will be