Question
Carbene intennediates are produced by the photo lysis of diazomethane or ketene . They are also produced by the reaction of with base or by Simmons-Smith reaction. There are two types of carbenes, singlet and triplet. They are so called due to their spin state.
Which carbene is produced in the following reactions
- CCIBr
- CBrI
- CCII
- All
The correct answer is: All
Related Questions to study
How many number of compounds, which have same IUPAC name
How many number of compounds, which have same IUPAC name
What is the sum of positions assigned to bromine while numbering the Parent Chain in the below caponiids ?
What is the sum of positions assigned to bromine while numbering the Parent Chain in the below caponiids ?
Many organic compounds contain more than one functional group. Which of the following is both an aldehyde and an ether
i)
ii)
iii)
iv)
v)
Many organic compounds contain more than one functional group. Which of the following is both an aldehyde and an ether
i)
ii)
iii)
iv)
v)
The IUPAC name of the following compound is:
The IUPAC name of the following compound is:
If the line x + y = k is a normal to the parabola y2 = 4x,then the value of k will be-
the equation of tangent and normal in terms of the slope of the parabola are used to find the equations for any given slope.
If the line x + y = k is a normal to the parabola y2 = 4x,then the value of k will be-
the equation of tangent and normal in terms of the slope of the parabola are used to find the equations for any given slope.
The equation of the normal to the parabola x2 = 8y whose slope is 1/m is
equations of normal and tangent in terms of the slope are used to find the normal and tangent for any given slope.
The equation of the normal to the parabola x2 = 8y whose slope is 1/m is
equations of normal and tangent in terms of the slope are used to find the normal and tangent for any given slope.
The equation of the normal to the parabola y2 + 12x = 0 at the upper end of it's latus rectum is
the normal and tangent are always perpendicular to each other at any given point. Therefore, the product of slopes of tangent and normal is equal to -1.
The equation of the normal to the parabola y2 + 12x = 0 at the upper end of it's latus rectum is
the normal and tangent are always perpendicular to each other at any given point. Therefore, the product of slopes of tangent and normal is equal to -1.
The equation of the normal having slope m of the parabola y2 = x + a is
parametric form of slope of parabola = y+tx = 2at + at^3
The equation of the normal having slope m of the parabola y2 = x + a is
parametric form of slope of parabola = y+tx = 2at + at^3
Find the equation of normal to the curve 2y = 3–x2 at the point (1, 1)
equation of straight line :
(y-y1)=m(x-x1)
Find the equation of normal to the curve 2y = 3–x2 at the point (1, 1)
equation of straight line :
(y-y1)=m(x-x1)
The equations of the normal at the ends of the latus rectum of the parabola y2 = 4ax are given by-
the slope of normal = -1/ slope of tangent.
Equation of both normals can be generalized by multiplying both the equations.
The equations of the normal at the ends of the latus rectum of the parabola y2 = 4ax are given by-
the slope of normal = -1/ slope of tangent.
Equation of both normals can be generalized by multiplying both the equations.
The line x + my + n = 0 is a normal to the parabola y2 = 4 ax if-
equation of normal of a parabola is given by:
y = -tx + 2at + at3
The line x + my + n = 0 is a normal to the parabola y2 = 4 ax if-
equation of normal of a parabola is given by:
y = -tx + 2at + at3
The equation of the normal to the parabola y2 = 16 x with slope – 1/4 is-
equation of normal of a parabola is given by:
y = -tx + 2at + at3
equation of normal in slope form: y = mx – 2am – am3
The equation of the normal to the parabola y2 = 16 x with slope – 1/4 is-
equation of normal of a parabola is given by:
y = -tx + 2at + at3
equation of normal in slope form: y = mx – 2am – am3
The equation of normal on point (2,4) to the parabola y2 = 8x is-
we can also use equation of normal in slope form: y = mx – 2am – am3
The equation of normal on point (2,4) to the parabola y2 = 8x is-
we can also use equation of normal in slope form: y = mx – 2am – am3
Area of triangle formed by the tangents at three points t1, t2 and t3 of the parabola y2 = 4ax is-
area under a triangle is given by the determinant of the vertex points of the triangle.
Area of triangle formed by the tangents at three points t1, t2 and t3 of the parabola y2 = 4ax is-
area under a triangle is given by the determinant of the vertex points of the triangle.
The equation of the common tangents to the parabolas y2 = 4x and x2 = 32y is-
the equation of tangent to the parabola y2= 4ax is y = mx + a/m
The equation of the common tangents to the parabolas y2 = 4x and x2 = 32y is-
the equation of tangent to the parabola y2= 4ax is y = mx + a/m