Chemistry-
General
Easy

Question

Decreasing order of boiling point of I - IV follows

  1. I > II > III > IV    
  2. I > II > IV > III    
  3. IV > III > II > I    
  4. II > I > III > IV    

The correct answer is: I > II > III > IV

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Correct boiling point order for I to IV is

Correct boiling point order for I to IV is

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The correct order of dipole moment is :

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The increasing order of dipole moment of following compounds is :

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Which will have highest dipole moment ?

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Which will have higher dipole moment than

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The correct orders about compounds I and II are:

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Read the following graph and gives the answer for the following questions

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Read the following graph and gives the answer for the following questions

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S1 : Covalent and ionic radii of Nb and Ta are almost the same
S2 : Ionisation energies of transition elements decrease with increase in atomic number in a given group
S3 : Iodide of Millon's base is believed to have the structure
S4 : Yellow colour of C r O subscript 4 end subscript superscript 2 minus end superscript is due to d-d transition

S1 : Covalent and ionic radii of Nb and Ta are almost the same
S2 : Ionisation energies of transition elements decrease with increase in atomic number in a given group
S3 : Iodide of Millon's base is believed to have the structure
S4 : Yellow colour of C r O subscript 4 end subscript superscript 2 minus end superscript is due to d-d transition

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What is the final product (B) of this sequence :

What is the final product (B) of this sequence :

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Consider the following sequence of reactions

The products (A) and (B) are, respectively,

Consider the following sequence of reactions

The products (A) and (B) are, respectively,

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Consider the following reaction.

The product (A) is

Consider the following reaction.

The product (A) is

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Hofmann rearrangement
In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromine to give a primary amine that has one carbon lesser than starting amide. General reaction.

Mech :

If the migrating group is chiral then its configuration is retained. Electron releasing effects in the migrating group increases reactivity of Hofmann rearrangement

Hofmann rearrangement
In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromine to give a primary amine that has one carbon lesser than starting amide. General reaction.

Mech :

If the migrating group is chiral then its configuration is retained. Electron releasing effects in the migrating group increases reactivity of Hofmann rearrangement

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Hofmann rearrangement
In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromine to give a primary amine that has one carbon lesser than starting amide. General reaction.

Mech :

If the migrating group is chiral then its configuration is retained. Electron releasing effects in the migrating group increases reactivity of Hofmann rearrangement
Arrange the following amides according to their relative reactivity when react with Br2 in excess of strong base
I)
II)
III)
IV) <img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/582432/1/1074906/Picture715.png" alt="" width="173" height="78"

Hofmann rearrangement
In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromine to give a primary amine that has one carbon lesser than starting amide. General reaction.

Mech :

If the migrating group is chiral then its configuration is retained. Electron releasing effects in the migrating group increases reactivity of Hofmann rearrangement
Arrange the following amides according to their relative reactivity when react with Br2 in excess of strong base
I)
II)
III)
IV) <img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/582432/1/1074906/Picture715.png" alt="" width="173" height="78"

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