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Chemistry-

General

Easy

Question

Formula of the following silicate anion is

$S i O_{4}^{4 -}$
$S i_{2} O_{7}^{6 -}$
$S i_{2} O_{8}^{6 -}$
$S i_{3} O_{9}^{6 -}$

The correct answer is: $S i subscript 2 end subscript O subscript 7 end subscript superscript 6 minus end superscript$

Charge
Two $S i to the power of 4 plus end exponent plus 8$
Seven $O to the power of 2 minus end exponent minus 14$
$S i subscript 2 end subscript O subscript 7 end subscript superscript 6 minus end superscript$

Related Questions to study

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

Sulphide mineral + $CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M$ M
can be

chemistry-General

The adjoining figure gives the road plan of lanes connecting two parallel roads AB and FJ Aman walking on the road AB takes a turn at random to reach the road FJ It is known that he reaches the road FJ from $O$ by taking a straight line The chance that he moves on a straight line from the road AB to the road FJ is.

The adjoining figure gives the road plan of lanes connecting two parallel roads AB and FJ Aman walking on the road AB takes a turn at random to reach the road FJ It is known that he reaches the road FJ from $O$ by taking a straight line The chance that he moves on a straight line from the road AB to the road FJ is.

The value of $cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis$ is Zero if

The value of $cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis$ is Zero if

parallel

If $sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction$ =

If $sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction$ =

The value of $sin invisible function application 47 to the power of ring operator plus sin invisible function application 61 to the power of ring operator minus sin invisible function application 11 to the power of ring operator minus sin invisible function application 25 to the power of ring operator$ is

The value of $sin invisible function application 47 to the power of ring operator plus sin invisible function application 61 to the power of ring operator minus sin invisible function application 11 to the power of ring operator minus sin invisible function application 25 to the power of ring operator$ is

If ABC is a triangle and $tan space A over 2 comma tan space B over 2 comma tan space C over 2$ are H.P then the minimum value of $cot space B over 2$ is equal to

If ABC is a triangle and $tan space A over 2 comma tan space B over 2 comma tan space C over 2$ are H.P then the minimum value of $cot space B over 2$ is equal to

parallel

If $theta equals pi over 2 to the power of n plus 1 end exponent$ then $cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta$ is equal to

If $theta equals pi over 2 to the power of n plus 1 end exponent$ then $cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta$ is equal to

If A,B,C re in A.P and $B equals pi over 4$ then $tan space A tan space B tan C$ =

If A,B,C re in A.P and $B equals pi over 4$ then $tan space A tan space B tan C$ =

If $alpha comma beta comma gamma$ do not differ by a multiple of $straight pi$ and if $fraction numerator cos space left parenthesis alpha plus theta right parenthesis over denominator sin space left parenthesis beta plus gamma right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis beta plus theta right parenthesis over denominator sin begin display style space end style left parenthesis gamma plus alpha right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis gamma plus theta right parenthesis over denominator sin begin display style space end style left parenthesis alpha plus beta right parenthesis end fraction equals k$ Then k equals

If $alpha comma beta comma gamma$ do not differ by a multiple of $straight pi$ and if $fraction numerator cos space left parenthesis alpha plus theta right parenthesis over denominator sin space left parenthesis beta plus gamma right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis beta plus theta right parenthesis over denominator sin begin display style space end style left parenthesis gamma plus alpha right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis gamma plus theta right parenthesis over denominator sin begin display style space end style left parenthesis alpha plus beta right parenthesis end fraction equals k$ Then k equals

parallel

From the figure AOC=

From the figure AOC=

In $capital delta$ ABC, D,E,F are the midpoints of sides BC, CA and AB respectively then ar $open parentheses B D E F close parentheses equals$

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When the solute has been added in the solution, then following observation can be made ?

When the solute has been added in the solution, then following observation can be made ?

parallel

B can be obtained from halide by van Arkel method. This involves reaction

B can be obtained from halide by van Arkel method. This involves reaction

chemistry-General

If $tan space open parentheses x plus pi over 4 close parentheses equals a$ then $sec squared space x$ =

If $tan space open parentheses x plus pi over 4 close parentheses equals a$ then $sec squared space x$ =

$sin space pi over 7 sin space fraction numerator 2 pi over denominator 7 end fraction sin space fraction numerator 4 pi over denominator 7 end fraction$ =

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parallel

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