In a set of reactions, m-bromo benzoic acid gave a product ‘D’. Identify the product.

 Compound C in the above reaction is

Compounds of general formula are called

The liquid in the watch glass in the following figure is :-

we can summarize the sum of GP formulas as follows:

• S∞ = a / (1 - r) when |r| < 1
• S∞ = ±∞, when |r| ≥ 1

 The IUPAC name of ‘B’ is

Match the reactant in Column-I with the reaction in Column-II

A semi circular current carrying wire having radius R is placed in plane with its centre at origin 'O'. There is non–uniform magnetic field (here B0 is +ve constant) is existing in the region. The magnetic force acting on semicircular wire will be along

A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width at angle to the boundary of magnetic field. Find the angle in the diagram.

A charged particle enters a uniform magnetic field perpendicular to its initial direction travelling in air. The path of the particle is seen to follow the path in figure. Which of statements 1–3 is /are correct?
1) The magnetic field strength may have been increased while the particle was travelling in air
2) The particle lost energy by ionizing the air
3) The particle lost charge by ionizing the air

Collin’s reagent causes the conversion

A particle having charge q enters a region of uniform magnetic field (directed inwards) and is deflected a distance x after travelling a distance y. The magnitude of the momentum of the particle is

Net magnetic field at the centre of the circle O due to a current carrying loop as shown in figure is

A nonconducting disc having uniform positive charge Q, is rotating about its axis with uniform angular velocity . The magnetic field at the centre of the disc is–

Two insulated rings, one of slightly smaller diameter than the other, are suspended along their common diameter as shown. Initially the planes of the rings are mutually perpendicular. When a steady current is set up in each of them.

 In the above reaction X is