Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

In the froth floatation process for the purification of minerals the particles float because :

they are light.
they are insoluble.
their surface is preferentially wetted by oil.
they bear an electrostatic charge.

The correct answer is: their surface is preferentially wetted by oil.

Related Questions to study

Statement‐I: The function $f left parenthesis x right parenthesis equals not stretchy integral subscript 0 end subscript superscript x end superscript square root of 1 plus t to the power of 2 end exponent end root d t$ is an odd function and $g left parenthesis x right parenthesis equals f to the power of ’ end exponent left parenthesis x right parenthesis$ is an even function.
Statement‐II: For a differentiable function $f left parenthesis x right parenthesis$ if $f to the power of ’ end exponent left parenthesis x right parenthesis$ is an even function then $f left parenthesis x right parenthesis$ is an odd function.

Statement‐I: The function $f left parenthesis x right parenthesis equals not stretchy integral subscript 0 end subscript superscript x end superscript square root of 1 plus t to the power of 2 end exponent end root d t$ is an odd function and $g left parenthesis x right parenthesis equals f to the power of ’ end exponent left parenthesis x right parenthesis$ is an even function.
Statement‐II: For a differentiable function $f left parenthesis x right parenthesis$ if $f to the power of ’ end exponent left parenthesis x right parenthesis$ is an even function then $f left parenthesis x right parenthesis$ is an odd function.

Statement‐I:: $not stretchy integral subscript blank superscript blank 2 to the power of t a n to the power of negative 1 end exponent x end exponent d left parenthesis c o t to the power of negative 1 end exponent x right parenthesis equals fraction numerator 2 to the power of t w to the power of negative 1 end exponent x end exponent over denominator l n 2 end fraction plus c$
Statement‐II : $fraction numerator d over denominator d x end fraction left parenthesis a to the power of x end exponent plus c right parenthesis equals a to the power of x end exponent l n$ a

Statement‐I:: $not stretchy integral subscript blank superscript blank 2 to the power of t a n to the power of negative 1 end exponent x end exponent d left parenthesis c o t to the power of negative 1 end exponent x right parenthesis equals fraction numerator 2 to the power of t w to the power of negative 1 end exponent x end exponent over denominator l n 2 end fraction plus c$
Statement‐II : $fraction numerator d over denominator d x end fraction left parenthesis a to the power of x end exponent plus c right parenthesis equals a to the power of x end exponent l n$ a

The value of $not stretchy integral subscript blank superscript blank blank$ $x. fraction numerator l n left parenthesis x plus square root of 1 plus x to the power of 2 end exponent end root right parenthesis over denominator square root of 1 plus x to the power of 2 end exponent end root end fraction d x$ equals:

The value of $not stretchy integral subscript blank superscript blank blank$ $x. fraction numerator l n left parenthesis x plus square root of 1 plus x to the power of 2 end exponent end root right parenthesis over denominator square root of 1 plus x to the power of 2 end exponent end root end fraction d x$ equals:

parallel

$not stretchy integral subscript blank superscript blank fraction numerator d x over denominator blank c o s blank x minus blank s i n blank x end fraction$ is equal to‐

$not stretchy integral subscript blank superscript blank fraction numerator d x over denominator blank c o s blank x minus blank s i n blank x end fraction$ is equal to‐

$not stretchy integral subscript blank superscript blank fraction numerator x to the power of 4 end exponent minus 4 over denominator x to the power of 2 end exponent square root of 4 plus x to the power of 2 end exponent plus x to the power of 4 end exponent end root end fraction d x$ equals‐

$not stretchy integral subscript blank superscript blank fraction numerator x to the power of 4 end exponent minus 4 over denominator x to the power of 2 end exponent square root of 4 plus x to the power of 2 end exponent plus x to the power of 4 end exponent end root end fraction d x$ equals‐

If $f left parenthesis x right parenthesis equals not stretchy integral subscript blank superscript blank fraction numerator 2 blank s i n blank x minus blank s i n blank 2 x over denominator x to the power of 3 end exponent end fraction d x$ , where $x not equal to 0$ , then Limitx $rightwards arrow 0 f to the power of ´ end exponent left parenthesis x right parenthesis$ has the value

If $f left parenthesis x right parenthesis equals not stretchy integral subscript blank superscript blank fraction numerator 2 blank s i n blank x minus blank s i n blank 2 x over denominator x to the power of 3 end exponent end fraction d x$ , where $x not equal to 0$ , then Limitx $rightwards arrow 0 f to the power of ´ end exponent left parenthesis x right parenthesis$ has the value

parallel

$not stretchy integral subscript blank superscript blank fraction numerator left parenthesis 2 x plus 1 right parenthesis over denominator left parenthesis x to the power of 2 end exponent plus 4 x plus 1 right parenthesis to the power of 3 divided by 2 end exponent end fraction d x$

$not stretchy integral subscript blank superscript blank fraction numerator left parenthesis 2 x plus 1 right parenthesis over denominator left parenthesis x to the power of 2 end exponent plus 4 x plus 1 right parenthesis to the power of 3 divided by 2 end exponent end fraction d x$

The equation of the directrix of the parabola $y to the power of 2 end exponent plus 4 y plus 4 x plus 2 equals 0 comma$ $i s colon$

The equation of the directrix of the parabola $y to the power of 2 end exponent plus 4 y plus 4 x plus 2 equals 0 comma$ $i s colon$

The equation of the common tangent touching the circle $left parenthesis x minus 3 right parenthesis to the power of 2 end exponent plus y to the power of 2 end exponent equals 9$ and the parabola $y to the power of 2 end exponent equals 4 x$ above the $x$ ‐axis is:

The equation of the common tangent touching the circle $left parenthesis x minus 3 right parenthesis to the power of 2 end exponent plus y to the power of 2 end exponent equals 9$ and the parabola $y to the power of 2 end exponent equals 4 x$ above the $x$ ‐axis is:

parallel

If the line x‐1 =0 is the directrix of the parabola $y to the power of 2 end exponent minus k x plus 8 equals 0$ , then one of the values of $k$ is :

If the line x‐1 =0 is the directrix of the parabola $y to the power of 2 end exponent minus k x plus 8 equals 0$ , then one of the values of $k$ is :

Assertion (A): Three normals are drawn from the point $P$ ’ with slopes $m subscript 1 end subscript comma m subscript 2 end subscript comma m subscript 3 end subscript$ to the parabola $y to the power of 2 end exponent equals 4 x$ If locus of ‘ $P$ ’ with $m subscript 1 end subscript m subscript 2 end subscript equals alpha$ is a part of the parabola itself then $alpha equals 2$
Reason (R): If normals at $left parenthesis x subscript 1 end subscript comma y subscript 1 end subscript right parenthesis comma left parenthesis x subscript 2 end subscript comma y subscript 2 end subscript right parenthesis$ and $left parenthesis y subscript 3 end subscript comma y subscript 3 end subscript right parenthesis$ are concurrent then $y subscript 1 end subscript plus y subscript 2 end subscript plus y subscript 3 end subscript equals 0$

Assertion (A): Three normals are drawn from the point $P$ ’ with slopes $m subscript 1 end subscript comma m subscript 2 end subscript comma m subscript 3 end subscript$ to the parabola $y to the power of 2 end exponent equals 4 x$ If locus of ‘ $P$ ’ with $m subscript 1 end subscript m subscript 2 end subscript equals alpha$ is a part of the parabola itself then $alpha equals 2$
Reason (R): If normals at $left parenthesis x subscript 1 end subscript comma y subscript 1 end subscript right parenthesis comma left parenthesis x subscript 2 end subscript comma y subscript 2 end subscript right parenthesis$ and $left parenthesis y subscript 3 end subscript comma y subscript 3 end subscript right parenthesis$ are concurrent then $y subscript 1 end subscript plus y subscript 2 end subscript plus y subscript 3 end subscript equals 0$

ABCD and EFGC are squares and the curve $y equals k square root of x$ passes through the origin $D$ and the points $B$ and F The ratio $fraction numerator F G over denominator B C end fraction$ is:

ABCD and EFGC are squares and the curve $y equals k square root of x$ passes through the origin $D$ and the points $B$ and F The ratio $fraction numerator F G over denominator B C end fraction$ is:

parallel

Statement‐I :: With respect to a hyperbola $fraction numerator x to the power of 2 end exponent over denominator 9 end fraction minus fraction numerator y to the power of 2 end exponent over denominator 16 end fraction equals 1$ pependicular are drawn from a point (5, 0) on the lines $3 y plus-or-minus 4 x equals 0$ , then their feet lie on circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 16.$
Statement‐II :: If from any foci of a hyperbola perpendicular are drawn on the asymptotes of the hyperbola then their feet lie on auxiliary circle.

Statement‐I :: With respect to a hyperbola $fraction numerator x to the power of 2 end exponent over denominator 9 end fraction minus fraction numerator y to the power of 2 end exponent over denominator 16 end fraction equals 1$ pependicular are drawn from a point (5, 0) on the lines $3 y plus-or-minus 4 x equals 0$ , then their feet lie on circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 16.$
Statement‐II :: If from any foci of a hyperbola perpendicular are drawn on the asymptotes of the hyperbola then their feet lie on auxiliary circle.

A hyperbola, having the transverse axis of length $2 s i n$ , is confocal with the ellipse $3 x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 12$ Then its equation is ‐

A hyperbola, having the transverse axis of length $2 s i n$ , is confocal with the ellipse $3 x to the power of 2 end exponent plus 4 y to the power of 2 end exponent equals 12$ Then its equation is ‐

The latus rectum of the hyperbola $16 x to the power of 2 end exponent minus 9 y to the power of 2 end exponent equals 144$ is‐

The latus rectum of the hyperbola $16 x to the power of 2 end exponent minus 9 y to the power of 2 end exponent equals 144$ is‐

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.