Questions given below are based on the following experiment An oxyacid of phosphorus has the following properties Complete neutralization of the acid with sodium hydroxide solution gives an aqueous solution of sodium ion and oxy-acid anions in the ratio 2:1. When a solution of the acid is warmed with silver nitrate solution metallic silver is deposited What is the structure of the oxy-acid?

chemistry-

Study the following sequence of reactions:

$A$ is

chemistry-General

A particle is moved from (0, 0) to (a, a) under a force $stack F with rightwards arrow on top equals open parentheses 3 stack i with tilde on top plus 4 stack j with rightwards arrow on top close parentheses blank$ from two paths. Path 1 is OP and path 2 is OQP. Let $W subscript 1 end subscript$ and $W subscript 2 end subscript$ be the work done by this force in these two paths. Then:
S

In the figure shown all the surfaces are frictionless, and mass of the block, m = 1 kg. The block and wedge are held initially at rest. Now wedge is given a horizontal acceleration of 10 $m divided by s to the power of 2 end exponent$ by applying a force on the wedge, so that the block does not slip on the wedge. Then work done by the normal force in ground frame on the block in $square root of 3 blank$ seconds is:

With what minimum velocity $V subscript 0 end subscript$ should block be projected from left end A towards end B such that it reaches the other end B of conveyer belt moving with constant velocity v? Friction coefficient between block and belt is $mu$ .

A bob is suspended from a crane by a cable of length $l equals 5 blank$ m. The crane and load are moving at a constant speed $V subscript 0 end subscript$ . The crane is stopped by a bumper and the bob on the cable swings out an angle of $60 to the power of ring operator end exponent$ . The initial speed $v subscript 0 end subscript text is end text text end text text - end text open parentheses g equals 9.8 m divided by s to the power of 2 end exponent close parentheses$

If $A plus B plus C equals 270 to the power of ring operator end exponent$ then $c o s invisible function application 2 A plus c o s invisible function application 2 B plus c o s invisible function application 2 C equals$

If $A plus B plus C equals 270 to the power of ring operator end exponent$ then $s i n invisible function application 2 A plus s i n invisible function application 2 B plus s i n invisible function application 2 C equals$

If $s i n invisible function application left parenthesis y plus z minus x right parenthesis comma s i n invisible function application left parenthesis z plus x y right parenthesis comma s i n invisible function application left parenthesis x plus y minus z right parenthesis$ are in A.P. then $t a n invisible function application x comma t a n invisible function application y$ and $t a n invisible function application z$ are in

Maths-

In any $straight triangle A B C fraction numerator left parenthesis a plus b plus c right parenthesis left parenthesis b plus c minus a right parenthesis left parenthesis c plus a minus b right parenthesis left parenthesis a plus b minus c right parenthesis over denominator 4 b squared c squared end fraction equals$

s denotes the semi-perimeter of the triangle ABC, ∆ its area and R the radius of the circle circumscribing the triangle ABC i.e., R is the circum-radius.

In any $straight triangle A B C fraction numerator left parenthesis a plus b plus c right parenthesis left parenthesis b plus c minus a right parenthesis left parenthesis c plus a minus b right parenthesis left parenthesis a plus b minus c right parenthesis over denominator 4 b squared c squared end fraction equals$

Maths-General

s denotes the semi-perimeter of the triangle ABC, ∆ its area and R the radius of the circle circumscribing the triangle ABC i.e., R is the circum-radius.

In $straight triangle A B C sum a cubed Sin space left parenthesis B minus C right parenthesis equals$

If $A plus B plus C equals 90 to the power of ring operator end exponent$ then $s i n to the power of 2 end exponent invisible function application A plus s i n to the power of 2 end exponent invisible function application B plus s i n to the power of 2 end exponent invisible function application C equals$

If $A plus B plus C equals 0 to the power of ring operator end exponent$ then $c o s to the power of 2 end exponent invisible function application A plus c o s to the power of 2 end exponent invisible function application B plus c o s to the power of 2 end exponent invisible function application C equals$

Maths-

In $straight triangle A B C comma sum a left parenthesis sin space B minus sin space C right parenthesis equals$

The angles of the triangle ABC are denoted by A, B, C and the corresponding opposite sides by a, b, c.

In $straight triangle A B C comma sum a left parenthesis sin space B minus sin space C right parenthesis equals$

Maths-General

The angles of the triangle ABC are denoted by A, B, C and the corresponding opposite sides by a, b, c.