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Chemistry-

General

Easy

Question

Statement-1 : PbI₄ is a stable compound.
Statement-2 : Pb²⁺ ions with concentrated Solution of KI forms a Sol. uble complex

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
Statement-1 is True, Statement-2 is False
Statement-1 is False, Statement-2 is True.

The correct answer is: Statement-1 is False, Statement-2 is True.

Related Questions to study

Consider the following statements $S$ and $R$ : S: Both $s i n blank$ x&cos $x$ are decreasing functions in the interval $left parenthesis pi divided by 2 comma pi right parenthesis$ .
R: If a differentiable function decreases in an interval $left parenthesis a comma blank b right parenthesis$ , then its derivative also decreases in $left parenthesis a comma blank b right parenthesis$ Which of the following is true ?

Consider the following statements $S$ and $R$ : S: Both $s i n blank$ x&cos $x$ are decreasing functions in the interval $left parenthesis pi divided by 2 comma pi right parenthesis$ .
R: If a differentiable function decreases in an interval $left parenthesis a comma blank b right parenthesis$ , then its derivative also decreases in $left parenthesis a comma blank b right parenthesis$ Which of the following is true ?

A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank The two sides having fence are of same length $x$ The maximum area enclosed by the park is‐

A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank The two sides having fence are of same length $x$ The maximum area enclosed by the park is‐

Let $y equals f left parenthesis x right parenthesis$ be a thrice derivable fu nction such that $f left parenthesis a right parenthesis f left parenthesis b right parenthesis less than 0 comma$ $f left parenthesis b right parenthesis f left parenthesis c right parenthesis less than 0 comma$ $f left parenthesis c right parenthesis f left parenthesis d right parenthesis less than 0$ where $a less than b less than c less than d blank$ Also the equations $f$ (x) $equals$ O& $f to the power of ’ ’ end exponent left parenthesis x right parenthesis equals 0$ have no common roots.
Statement‐I:: The equation $f left parenthesis x right parenthesis left parenthesis f to the power of ’ ’ end exponent left parenthesis x right parenthesis right parenthesis to the power of 2 end exponent plus f left parenthesis x right parenthesis f to the power of ’ end exponent left parenthesis x right parenthesis f to the power of ’ ’ ’ end exponent left parenthesis x right parenthesis plus left parenthesis f to the power of ’ end exponent left parenthesis x right parenthesis right parenthesis to the power of 2 end exponent f to the power of ’ ’ end exponent left parenthesis x right parenthesis equals 0$ has atleast 5 real roots.
Statement‐II:: The equation $f left parenthesis x right parenthesis equals 0$ has atleast 3 real distinct roots&if $f left parenthesis x right parenthesis equals 0$ has $k$ real distinct roots, then $f to the power of ´ end exponent left parenthesis x right parenthesis equals 0$ has atleast k‐l distinct roots.

Let $y equals f left parenthesis x right parenthesis$ be a thrice derivable fu nction such that $f left parenthesis a right parenthesis f left parenthesis b right parenthesis less than 0 comma$ $f left parenthesis b right parenthesis f left parenthesis c right parenthesis less than 0 comma$ $f left parenthesis c right parenthesis f left parenthesis d right parenthesis less than 0$ where $a less than b less than c less than d blank$ Also the equations $f$ (x) $equals$ O& $f to the power of ’ ’ end exponent left parenthesis x right parenthesis equals 0$ have no common roots.
Statement‐I:: The equation $f left parenthesis x right parenthesis left parenthesis f to the power of ’ ’ end exponent left parenthesis x right parenthesis right parenthesis to the power of 2 end exponent plus f left parenthesis x right parenthesis f to the power of ’ end exponent left parenthesis x right parenthesis f to the power of ’ ’ ’ end exponent left parenthesis x right parenthesis plus left parenthesis f to the power of ’ end exponent left parenthesis x right parenthesis right parenthesis to the power of 2 end exponent f to the power of ’ ’ end exponent left parenthesis x right parenthesis equals 0$ has atleast 5 real roots.
Statement‐II:: The equation $f left parenthesis x right parenthesis equals 0$ has atleast 3 real distinct roots&if $f left parenthesis x right parenthesis equals 0$ has $k$ real distinct roots, then $f to the power of ´ end exponent left parenthesis x right parenthesis equals 0$ has atleast k‐l distinct roots.

parallel

Statement‐I:: The largest term in the sequence $a subscript n end subscript equals fraction numerator n to the power of 2 end exponent over denominator 3 end fraction n element of N$ is the $7 to the power of t h end exponent$ term.
$n plus 200$ ’
Statement‐II:: The function $f left parenthesis x right parenthesis equals fraction numerator x to the power of 2 end exponent over denominator x to the power of 3 end exponent plus 200 end fraction$ attains local maxima at $x equals 7.$

Statement‐I:: The largest term in the sequence $a subscript n end subscript equals fraction numerator n to the power of 2 end exponent over denominator 3 end fraction n element of N$ is the $7 to the power of t h end exponent$ term.
$n plus 200$ ’
Statement‐II:: The function $f left parenthesis x right parenthesis equals fraction numerator x to the power of 2 end exponent over denominator x to the power of 3 end exponent plus 200 end fraction$ attains local maxima at $x equals 7.$

The area of the region bounded in first quadrant by $y equals x to the power of 1 divided by 3 end exponent semicolon y equals negative x to the power of 2 end exponent plus 2 x plus 3 semicolon y equals 2 x minus 1$ and the axis of ordinates is:

The area of the region bounded in first quadrant by $y equals x to the power of 1 divided by 3 end exponent semicolon y equals negative x to the power of 2 end exponent plus 2 x plus 3 semicolon y equals 2 x minus 1$ and the axis of ordinates is:

The area of the region bounded by the curve $a to the power of 4 end exponent y to the power of 2 end exponent equals left parenthesis 2 a minus x right parenthesis x to the power of 5 end exponent$ is to that of the circle whose radius is $a$ , is given by the ratio

The area of the region bounded by the curve $a to the power of 4 end exponent y to the power of 2 end exponent equals left parenthesis 2 a minus x right parenthesis x to the power of 5 end exponent$ is to that of the circle whose radius is $a$ , is given by the ratio

parallel

Statement‐I : The area of the curve $y equals s i n to the power of 2 end exponent x$ from $0$ to $pi$ will be more than that of curve $y equals s stack m with dot on top x$ from $0$ to $pi.$
Statement‐II : $t to the power of 2 end exponent greater than t$ if $t element of R minus left square bracket O comma blank 1 right square bracket.$

Statement‐I : The area of the curve $y equals s i n to the power of 2 end exponent x$ from $0$ to $pi$ will be more than that of curve $y equals s stack m with dot on top x$ from $0$ to $pi.$
Statement‐II : $t to the power of 2 end exponent greater than t$ if $t element of R minus left square bracket O comma blank 1 right square bracket.$

The area bounded by the curve y=f(x) , the $x$ ‐axis &the ordinates x=1 &x =b is (b‐l)sin $left parenthesis 3 b plus 4 right parenthesis$ Then f(x) is:

The area bounded by the curve y=f(x) , the $x$ ‐axis &the ordinates x=1 &x =b is (b‐l)sin $left parenthesis 3 b plus 4 right parenthesis$ Then f(x) is:

The value of $not stretchy integral subscript a end subscript superscript b end superscript left parenthesis x minus a right parenthesis to the power of 3 end exponent left parenthesis b blank short dash x right parenthesis$ 4dx is $fraction numerator left parenthesis b minus a right parenthesis to the power of m end exponent over denominator n end fraction$ Then $left parenthesis m comma blank n right parenthesis$ is

The value of $not stretchy integral subscript a end subscript superscript b end superscript left parenthesis x minus a right parenthesis to the power of 3 end exponent left parenthesis b blank short dash x right parenthesis$ 4dx is $fraction numerator left parenthesis b minus a right parenthesis to the power of m end exponent over denominator n end fraction$ Then $left parenthesis m comma blank n right parenthesis$ is

parallel

The tangent to the graph of the function $y equals f left parenthesis x right parenthesis$ at the point with abscissa $x equals 1$ form an angle of $pi divided by 6$ and at the point $x equals 2$ , an angle of $pi divided by 3$ and at the point $x equals 3$ , an angle of $pi divided by 4$ The value of $not stretchy integral subscript 1 end subscript superscript 3 end superscript f to the power of ’ end exponent left parenthesis x right parenthesis f to the power of ’ ’ end exponent left parenthesis x right parenthesis d x plus not stretchy integral subscript 2 end subscript superscript 3 end superscript f to the power of ’ ’ end exponent left parenthesis x right parenthesis d x$ ( $f to the power of ’ end exponent left parenthesis x right parenthesis$ is supposed to be continuous) is:

The tangent to the graph of the function $y equals f left parenthesis x right parenthesis$ at the point with abscissa $x equals 1$ form an angle of $pi divided by 6$ and at the point $x equals 2$ , an angle of $pi divided by 3$ and at the point $x equals 3$ , an angle of $pi divided by 4$ The value of $not stretchy integral subscript 1 end subscript superscript 3 end superscript f to the power of ’ end exponent left parenthesis x right parenthesis f to the power of ’ ’ end exponent left parenthesis x right parenthesis d x plus not stretchy integral subscript 2 end subscript superscript 3 end superscript f to the power of ’ ’ end exponent left parenthesis x right parenthesis d x$ ( $f to the power of ’ end exponent left parenthesis x right parenthesis$ is supposed to be continuous) is:

The integral $stretchy integral subscript negative fraction numerator 1 over denominator 2 end fraction end subscript superscript fraction numerator 1 over denominator 2 end fraction end superscript open parentheses left square bracket x right square bracket plus l n open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses close parentheses d x$ equals‐

The integral $stretchy integral subscript negative fraction numerator 1 over denominator 2 end fraction end subscript superscript fraction numerator 1 over denominator 2 end fraction end superscript open parentheses left square bracket x right square bracket plus l n open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses close parentheses d x$ equals‐

If $g left parenthesis x right parenthesis equals not stretchy integral subscript 0 end subscript superscript x end superscript blank c o s blank 4 t d t$ , then $g left parenthesis x plus pi right parenthesis$ equals :

If $g left parenthesis x right parenthesis equals not stretchy integral subscript 0 end subscript superscript x end superscript blank c o s blank 4 t d t$ , then $g left parenthesis x plus pi right parenthesis$ equals :

parallel

The figure shows a network of four resistances and three batteries Choose the correct alternative

The figure shows a network of four resistances and three batteries Choose the correct alternative

physics-General

The figure shows a network of resistances in which the point A is earthed.
The point which has the least potential is

The figure shows a network of resistances in which the point A is earthed.
The point which has the least potential is

physics-General

The figure shows a network of five resistances and two batteries The current through the 30V battery is

The figure shows a network of five resistances and two batteries The current through the 30V battery is

physics-General

parallel

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