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Chemistry-

General

Easy

Question

Statement (A) : Mercury is a liquid.
Statement (B) : Bromine is a gas.

A is true
B is false
Both are true
Both A and B are false

The correct answer is: A is true

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If the independent variable $x$ is changed to $y$ , then the differential equation $x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0$ is transformed to $x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k$ , k being a number Then k equals

If the independent variable $x$ is changed to $y$ , then the differential equation $x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0$ is transformed to $x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k$ , k being a number Then k equals

parallel

The differential equation $e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0$ has the particular solution $y left parenthesis O right parenthesis equals 1$ The value of $x$ , when $y equals 0$ , is

The differential equation $e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0$ has the particular solution $y left parenthesis O right parenthesis equals 1$ The value of $x$ , when $y equals 0$ , is

If a, b, $c$ , are real numbers, and $D equals open vertical bar table row a cell 1 plus 2 i end cell cell 3 minus 5 i end cell row cell 1 minus 2 i end cell b cell negative 7 minus 3 i end cell row cell 3 plus 5 i end cell cell negative 7 plus 3 i end cell c end table close vertical bar$ then D is

If a, b, $c$ , are real numbers, and $D equals open vertical bar table row a cell 1 plus 2 i end cell cell 3 minus 5 i end cell row cell 1 minus 2 i end cell b cell negative 7 minus 3 i end cell row cell 3 plus 5 i end cell cell negative 7 plus 3 i end cell c end table close vertical bar$ then D is

The value of $lambda$ for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

Hence λ=−2 for no solution.

The value of $lambda$ for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

Hence λ=−2 for no solution.

parallel

The number of values of $k$ for which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 possess a non‐zero solution is :‐

The number of values of $k$ for which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 possess a non‐zero solution is :‐

If $a subscript 1 end subscript comma$ $a subscript 2 end subscript comma horizontal ellipsis horizontal ellipsis. a subscript n end subscript comma$ $a subscript n plus 1 end subscript$ are in $G P blank a n d blank a subscript i end subscript greater than 0 for all i comma$ then $open vertical bar table row cell l o g invisible function application a subscript n end subscript end cell cell l o g invisible function application a subscript n plus 2 end subscript end cell cell l o g invisible function application a subscript n plus 4 end subscript end cell row cell l o g invisible function application a subscript n plus 6 end subscript end cell cell l o g invisible function application a subscript n plus 8 end subscript end cell cell l o g invisible function application a subscript n plus 10 end subscript end cell row cell l o g invisible function application a subscript n plus 12 end subscript end cell cell l o g invisible function application a subscript n plus 14 end subscript end cell cell l o g invisible function application a subscript n plus 16 end subscript end cell end table close vertical bar$ is equal to

If $a subscript 1 end subscript comma$ $a subscript 2 end subscript comma horizontal ellipsis horizontal ellipsis. a subscript n end subscript comma$ $a subscript n plus 1 end subscript$ are in $G P blank a n d blank a subscript i end subscript greater than 0 for all i comma$ then $open vertical bar table row cell l o g invisible function application a subscript n end subscript end cell cell l o g invisible function application a subscript n plus 2 end subscript end cell cell l o g invisible function application a subscript n plus 4 end subscript end cell row cell l o g invisible function application a subscript n plus 6 end subscript end cell cell l o g invisible function application a subscript n plus 8 end subscript end cell cell l o g invisible function application a subscript n plus 10 end subscript end cell row cell l o g invisible function application a subscript n plus 12 end subscript end cell cell l o g invisible function application a subscript n plus 14 end subscript end cell cell l o g invisible function application a subscript n plus 16 end subscript end cell end table close vertical bar$ is equal to

If $a comma$ $b comma$ $c$ are real then the value of determinant $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell a b end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell a c end cell cell b c end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar equals 1$ if

If $a comma$ $b comma$ $c$ are real then the value of determinant $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell a b end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell a c end cell cell b c end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar equals 1$ if

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