Chemistry-
General
Easy

Question

The molecules in liquid can slip over each other because the intermolecular forces are.....

  1. Very strong    
  2. Strong    
  3. Weak    
  4. All the above    

The correct answer is: Weak

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The intermolecular space in solids is......

The intermolecular space in solids is......

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Statement (A) : Mercury is a liquid.
Statement (B) : Bromine is a gas.

Statement (A) : Mercury is a liquid.
Statement (B) : Bromine is a gas.

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The smallest particle of an element or compound that has independent existence is.....

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If the independent variable x is changed to y, then the differential equation x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0 is transformed to x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k, k being a number Then k equals

If the independent variable x is changed to y, then the differential equation x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0 is transformed to x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k, k being a number Then k equals

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The differential equation e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0 has the particular solution y left parenthesis O right parenthesis equals 1 The value of x, when y equals 0, is

The differential equation e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0 has the particular solution y left parenthesis O right parenthesis equals 1 The value of x, when y equals 0, is

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If a, b, c, are real numbers, and D equals open vertical bar table row a cell 1 plus 2 i end cell cell 3 minus 5 i end cell row cell 1 minus 2 i end cell b cell negative 7 minus 3 i end cell row cell 3 plus 5 i end cell cell negative 7 plus 3 i end cell c end table close vertical bar then D is

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The value of lambda for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

Hence λ=2 for no solution.

The value of lambda for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

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Hence λ=2 for no solution.

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The number of values of k for which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 possess a non‐zero solution is :‐

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