Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

Which of the following fibres is not obtained from plants ?

Linen
Cotton
Silk
Jute

The correct answer is: Silk

Related Questions to study

Which of the following is a hand woven fabric?

Which of the following is a hand woven fabric?

chemistry-General

Which of the following is used for coating a non-stick pan

Which of the following is used for coating a non-stick pan

chemistry-General

Which of the following properties of synthetic plastic makes it the most convenient to use ?

Which of the following properties of synthetic plastic makes it the most convenient to use ?

chemistry-General

parallel

The raw material which is used in padding the interior parts of automobiles is .....

The raw material which is used in padding the interior parts of automobiles is .....

chemistry-General

If the independent variable $x$ is changed to $y$ , then the differential equation $x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0$ is transformed to $x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k$ , k being a number Then k equals

If the independent variable $x$ is changed to $y$ , then the differential equation $x fraction numerator d to the power of 2 end exponent y over denominator d x to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d y over denominator d x end fraction right parenthesis to the power of 3 end exponent minus fraction numerator d y over denominator d x end fraction equals 0$ is transformed to $x fraction numerator d to the power of 2 end exponent x over denominator d y to the power of 2 end exponent end fraction plus left parenthesis fraction numerator d x over denominator d y end fraction right parenthesis to the power of 2 end exponent equals k$ , k being a number Then k equals

The differential equation $e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0$ has the particular solution $y left parenthesis O right parenthesis equals 1$ The value of $x$ , when $y equals 0$ , is

The differential equation $e to the power of y end exponent d x plus left parenthesis e to the power of y end exponent. x plus 2 y right parenthesis d y equals 0$ has the particular solution $y left parenthesis O right parenthesis equals 1$ The value of $x$ , when $y equals 0$ , is

parallel

If a, b, $c$ , are real numbers, and $D equals open vertical bar table row a cell 1 plus 2 i end cell cell 3 minus 5 i end cell row cell 1 minus 2 i end cell b cell negative 7 minus 3 i end cell row cell 3 plus 5 i end cell cell negative 7 plus 3 i end cell c end table close vertical bar$ then D is

If a, b, $c$ , are real numbers, and $D equals open vertical bar table row a cell 1 plus 2 i end cell cell 3 minus 5 i end cell row cell 1 minus 2 i end cell b cell negative 7 minus 3 i end cell row cell 3 plus 5 i end cell cell negative 7 plus 3 i end cell c end table close vertical bar$ then D is

The value of $lambda$ for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

Hence λ=−2 for no solution.

The value of $lambda$ for which the system ofequations 2x-y-z=12, x-2y+z=-4, x+y+λz=4 has no solution is

Hence λ=−2 for no solution.

The number of values of $k$ for which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 possess a non‐zero solution is :‐

The number of values of $k$ for which the linear equations 4x+ky+2z=0 kx+4y+z=0 2x+2y+z=0 possess a non‐zero solution is :‐

parallel

If $a subscript 1 end subscript comma$ $a subscript 2 end subscript comma horizontal ellipsis horizontal ellipsis. a subscript n end subscript comma$ $a subscript n plus 1 end subscript$ are in $G P blank a n d blank a subscript i end subscript greater than 0 for all i comma$ then $open vertical bar table row cell l o g invisible function application a subscript n end subscript end cell cell l o g invisible function application a subscript n plus 2 end subscript end cell cell l o g invisible function application a subscript n plus 4 end subscript end cell row cell l o g invisible function application a subscript n plus 6 end subscript end cell cell l o g invisible function application a subscript n plus 8 end subscript end cell cell l o g invisible function application a subscript n plus 10 end subscript end cell row cell l o g invisible function application a subscript n plus 12 end subscript end cell cell l o g invisible function application a subscript n plus 14 end subscript end cell cell l o g invisible function application a subscript n plus 16 end subscript end cell end table close vertical bar$ is equal to

If $a subscript 1 end subscript comma$ $a subscript 2 end subscript comma horizontal ellipsis horizontal ellipsis. a subscript n end subscript comma$ $a subscript n plus 1 end subscript$ are in $G P blank a n d blank a subscript i end subscript greater than 0 for all i comma$ then $open vertical bar table row cell l o g invisible function application a subscript n end subscript end cell cell l o g invisible function application a subscript n plus 2 end subscript end cell cell l o g invisible function application a subscript n plus 4 end subscript end cell row cell l o g invisible function application a subscript n plus 6 end subscript end cell cell l o g invisible function application a subscript n plus 8 end subscript end cell cell l o g invisible function application a subscript n plus 10 end subscript end cell row cell l o g invisible function application a subscript n plus 12 end subscript end cell cell l o g invisible function application a subscript n plus 14 end subscript end cell cell l o g invisible function application a subscript n plus 16 end subscript end cell end table close vertical bar$ is equal to

If $a comma$ $b comma$ $c$ are real then the value of determinant $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell a b end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell a c end cell cell b c end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar equals 1$ if

If $a comma$ $b comma$ $c$ are real then the value of determinant $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell a b end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell a c end cell cell b c end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar equals 1$ if

The system of linear equations x+y-z=6, x+2y-3z=14 and $2 x plus 5 y minus lambda z equals 9 left parenthesis lambda element of R right parenthesis$ has a unique solution if

Hence option B is the correct option

The system of linear equations x+y-z=6, x+2y-3z=14 and $2 x plus 5 y minus lambda z equals 9 left parenthesis lambda element of R right parenthesis$ has a unique solution if

Hence option B is the correct option

parallel

If $D equals$ $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell b a end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell c a end cell cell c b end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar$ then $D equals$

If $D equals$ $open vertical bar table row cell a to the power of 2 end exponent plus 1 end cell cell a b end cell cell a c end cell row cell b a end cell cell b to the power of 2 end exponent plus 1 end cell cell b c end cell row cell c a end cell cell c b end cell cell c to the power of 2 end exponent plus 1 end cell end table close vertical bar$ then $D equals$

Let $A equals open curly brackets table attributes columnalign left end attributes row cell c o s to the power of negative 1 end exponent x end cell cell c o s to the power of negative 1 end exponent y end cell cell c o s to the power of negative 1 end exponent end cell z row cell c o s to the power of negative 1 end exponent y end cell cell c o s to the power of negative 1 end exponent z end cell cell c o s to the power of negative 1 end exponent x end cell blank row cell c o s to the power of negative 1 end exponent z end cell cell c o s to the power of negative 1 end exponent x end cell cell c o s to the power of negative 1 end exponent y end cell blank end table close curly brackets$ such that $vertical line A vertical line equals 0$ , then maximum value of $x plus y plus z$ is

Let $A equals open curly brackets table attributes columnalign left end attributes row cell c o s to the power of negative 1 end exponent x end cell cell c o s to the power of negative 1 end exponent y end cell cell c o s to the power of negative 1 end exponent end cell z row cell c o s to the power of negative 1 end exponent y end cell cell c o s to the power of negative 1 end exponent z end cell cell c o s to the power of negative 1 end exponent x end cell blank row cell c o s to the power of negative 1 end exponent z end cell cell c o s to the power of negative 1 end exponent x end cell cell c o s to the power of negative 1 end exponent y end cell blank end table close curly brackets$ such that $vertical line A vertical line equals 0$ , then maximum value of $x plus y plus z$ is

Statement‐I : The inverse of the matrix $A equals left square bracket a subscript i j end subscript right square bracket subscript n cross times n end subscript$ where $a subscript i j end subscript equals 0 comma$ $i greater or equal than j$ is $B equals left square bracket a subscript i j to the power of negative 1 end exponent end subscript right square bracket subscript n cross times n end subscript$
Statement‐II : The inverse of singular matrix does not exist.

Hence option D is the suitable option

Statement‐I : The inverse of the matrix $A equals left square bracket a subscript i j end subscript right square bracket subscript n cross times n end subscript$ where $a subscript i j end subscript equals 0 comma$ $i greater or equal than j$ is $B equals left square bracket a subscript i j to the power of negative 1 end exponent end subscript right square bracket subscript n cross times n end subscript$
Statement‐II : The inverse of singular matrix does not exist.

Hence option D is the suitable option

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.