Question
Find the area of the figure.
.
Hint:
The figure consists of 1 rhombus and 1 trapezium
So, Area of figure = area of rhombus EFGH + area of trapezium ABCD .
The correct answer is: 340 cm2
Ans :- 340 cm2.
Explanation :-
By observing the diagram EFGH is a quadrilateral where all sides are equal so
EFGH is a rhombus .
ABCD is quadrilateral with AD // BC .
so, ABCD is trapezium with AD and BC as parallel sides.
STEP 1:- Find the area of rhombus EFGH
GE = 14 cm and HF = 10 cm ( diagonals of rhombus EFGH)
Area of rhombus =
Area of rhombus =
We get area of rhombus EFGH is 70cm2.
STEP 2:- Find the area of trapezium ABCD
AD = 24 cm ; BC = 12 cm ;distance between parallel lines AD and BC = 15 cm
= 270 cm2
Area of trapezium ABCD is 270 cm2
Step 3:- Find the area of figure
Area of figure = area of rhombus EFGH + area of trapezium ABCD .
Area of figure = 70+270 = 340 cm2.
Therefore , the area of the entire figure is 340cm2.
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