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Question

Find the fifth term of the binomial expansion left parenthesis x plus y right parenthesis to the power of 5

hintHint:

The binomial expansion is left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of   n C subscript k x to the power of n minus k end exponent y to the power of k comma text  here  end text n greater or equal than 0
We are asked to find the fifth term of the binomial expansion of left parenthesis x plus y right parenthesis to the power of 5.

The correct answer is: 5xy4


    Step 1 of 2:
    The given expression is left parenthesis x plus y right parenthesis to the power of 5 . Here, the value of n=5. Thus, we will have n+1=5+1=6 terms.
    Step 2 of 2:
    Substitute the values in the binomial expansion to get the coefficients:

    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell left parenthesis x plus y right parenthesis to the power of 5 equals 5 C subscript 0 x to the power of 5 plus 5 C subscript 1 x to the power of 4 left parenthesis y right parenthesis plus 5 C subscript 2 x cubed open parentheses y squared close parentheses plus 5 C subscript 3 open parentheses x squared close parentheses open parentheses y cubed close parentheses plus 5 C subscript 4 left parenthesis x right parenthesis open parentheses y to the power of 4 close parentheses plus 5 C subscript 5 y to the power of 5 end cell row cell equals x to the power of 5 plus 5 x to the power of 4 y plus 10 x cubed y squared plus 10 x squared y cubed plus 5 x y to the power of 4 plus y to the power of 5 end cell end table
    Thus, the fifth term of the expansion is 5xy4 .

    The expansion of left parenthesis x plus y right parenthesis to the power of n has n+1 terms while expanding. The answer can be found using the Pascal’s triangle or binomial expansion.

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