Maths-
General
Easy

Question

Find the Quotient and the domain .
fraction numerator 25 straight x squared minus 4 over denominator straight x squared minus 9 end fraction divided by fraction numerator 5 straight x minus 2 over denominator straight x plus 3 end fraction

hintHint:

The expansions of certain identities are:
table attributes columnalign right columnspacing 0em end attributes row cell left parenthesis straight x plus straight a right parenthesis left parenthesis straight x plus straight b right parenthesis equals straight x squared plus left parenthesis straight a plus straight b right parenthesis straight x plus ab end cell row cell open parentheses straight x squared minus straight a squared close parentheses equals left parenthesis straight x minus straight a right parenthesis left parenthesis straight x plus straight a right parenthesis space space space space space space space space space space space space space space space end cell end table
Finding the quotient is same as division. Dividing a number and multiplying it with a reciprocal of the number have the same effect.
We are asked to find the quotient and the domain of the expression.

The correct answer is: Hence, the domain is, (-∞,3)∪(3,∞).


    Step 1 of 3:
    The given expression is, fraction numerator 25 x squared minus 4 over denominator x squared minus 9 end fraction divided by fraction numerator 5 x minus 2 over denominator x plus 3 end fraction.
    Now, take the reciprocal of the second expression and multiply them,
    fraction numerator 25 x squared minus 4 over denominator x squared minus 9 end fraction cross times fraction numerator x plus 3 over denominator 5 x minus 2 end fraction
    Step 2 of 3:
    Simplify the expression and cancel out the common factors,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell fraction numerator 25 x squared minus 4 over denominator x squared minus 9 end fraction cross times fraction numerator x plus 3 over denominator 5 x minus 2 end fraction equals fraction numerator left parenthesis 5 x right parenthesis squared minus 2 squared over denominator x squared minus 3 squared end fraction cross times fraction numerator x plus 3 over denominator 5 x minus 2 end fraction end cell row cell equals fraction numerator left parenthesis 5 x minus 2 right parenthesis left parenthesis 5 x plus 2 right parenthesis over denominator left parenthesis x minus 3 right parenthesis left parenthesis x plus 3 right parenthesis end fraction cross times fraction numerator x plus 3 over denominator 5 x minus 2 end fraction space space space space space space space space space space space space space space space space space space space space space space space end cell row cell equals fraction numerator left parenthesis 5 x plus 2 right parenthesis over denominator left parenthesis x minus 3 right parenthesis end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space end cell end table
    Thus, the quotient is, fraction numerator left parenthesis 5 x plus 2 right parenthesis over denominator left parenthesis x minus 3 right parenthesis end fraction.
    Step 3 of 3:
    The domain of a rational expression should exclude the value for which the denominator attains a zero value. Thus, we have:
    table attributes columnalign right columnspacing 0em end attributes row cell straight x minus 3 equals 0 end cell row cell straight x equals 3 space space space space space space end cell end table
    Hence, the domain is, -∞,3)∪(3,∞).

    We have to state the domain of a rational expression while simplifying them because we must exclude zeros of a denominator as dividing with zero is not defined.

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