Maths-
General
Easy

Question

Find the solution of the system of equations.
y equals x squared plus 3 x minus 2
Y= 2x

hintHint:

A quadratic equation of the form x squared plus open parentheses a plus b close parentheses x plus a b can be simplified into open parentheses x plus a right parenthesis left parenthesis x plus b close parentheses. This can be further solved by equating it to zero.
We are asked to solve the set of equation.

The correct answer is: We are asked to solve the set of equation.


    Step 1 of 3:
    The LHS of the given set of equation is equal. Hence, we can equate them:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x squared plus 3 x minus 2 equals 2 x space space space space space end cell row cell x squared plus 3 x minus 2 x minus 2 equals 0 end cell row cell x squared plus x minus 2 equals 0 space space space space space space space space space space space end cell end table
    Step 2 of 3:
    Solve the equation for the variable x:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x squared plus x minus 2 equals 0 space space space space space space space space space space space space space space end cell row cell x squared plus 2 x minus x minus 2 equals 0 space space space space space space end cell row cell x left parenthesis x plus 2 right parenthesis minus 1 left parenthesis x plus 2 right parenthesis equals 0 space end cell row cell left parenthesis x minus 1 right parenthesis left parenthesis x plus 2 right parenthesis equals 0 space space space space space space space space space space end cell row cell x equals 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space end cell row cell x equals negative 2 space space space space space space space space space space space space space space space space space space space space space space space space space end cell end table
    Step 3 of 3:
    Now, substitute the values of x in any of the equation, to get values of y:
    When x=1,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals 2 x space space end cell row cell y equals 2 left parenthesis 1 right parenthesis end cell row cell y equals 2 space space space space space end cell end table
    When x=-2,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals 2 x space space space space space space end cell row cell y equals 2 left parenthesis negative 2 right parenthesis end cell row cell y equals negative 4 space space space space space end cell end table
    Thus, the solutions of the set are: (1, 2) and (-2, -4)
     

    A quadratic equation can have a maximum of two real roots. There are instances where it has no real roots.

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