Maths-
General
Easy

Question

Find the vertex, axis of symmetry and sketch the graph of the function f(x)= x2 -5

hintHint:

The vertex form of a quadratic function is
f(x) = a(x – h)2 + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.
 

The correct answer is: Hence, the vertex of the parabola is (0,-5) and the axis of the symmetry is x = 0


    Given, f(x) =x2 -5
    Here, h = 0, k = -5
    So, the vertex of the parabola is (0,-5) and the axis of the symmetry is x = 0
    The graph can be plotted as

    Final Answer:
    Hence, the vertex of the parabola is (0,-5) and the axis of the symmetry is x = 0.

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