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    Physics
    General
    Easy

    Question

    Here are the graphs of x→ t of moving body. which of them is not suitable?

    The correct answer is:

    Related Questions to study

    General
    Maths-

    A cubic polynomial f(x) = ax3 + bx2 + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

    I f space a space f u n c t i o n space h a s space a space tan g e n t space a t space a space p o i n t space x equals a space comma space t h e n comma space i t space m e a n s comma space i t space i s space t h e space c r i t i c a l space p o i n t space o f space t h a t space f u n c t i o n space a n d space t h e space d e r i v a t i v e space o f space t h e space f u n c t i o n space i s space z e r o space a t space t h a t space p o i n t. space P e r f o r m space t h e space c a l c u l a t i o n s space c a r e f u l l y comma space t o space a v o i d space s i l l y space m i s t a k e s. space O n e space s h o u l d space k n o w space h o w space t o space r e a d space a space g r a p h space t o space s o l v e space s u c h space q u e s t i o n s.

    A cubic polynomial f(x) = ax3 + bx2 + cx + d has a graph which touches the x-axis at 2, has another x-intercept at –1 and has y-intercept at –2 as shown. The value of, a + b + c + d equals

    Maths-General

    I f space a space f u n c t i o n space h a s space a space tan g e n t space a t space a space p o i n t space x equals a space comma space t h e n comma space i t space m e a n s comma space i t space i s space t h e space c r i t i c a l space p o i n t space o f space t h a t space f u n c t i o n space a n d space t h e space d e r i v a t i v e space o f space t h e space f u n c t i o n space i s space z e r o space a t space t h a t space p o i n t. space P e r f o r m space t h e space c a l c u l a t i o n s space c a r e f u l l y comma space t o space a v o i d space s i l l y space m i s t a k e s. space O n e space s h o u l d space k n o w space h o w space t o space r e a d space a space g r a p h space t o space s o l v e space s u c h space q u e s t i o n s.

    General
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    Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b sin invisible function application fraction numerator pi over denominator 2 end fraction x, 1 £ x £ 2 then which of the following is correct?

    Consider f(x) = |1–x| 1 £ x £ 2 and g(x )= f(x) + b sin invisible function application fraction numerator pi over denominator 2 end fraction x, 1 £ x £ 2 then which of the following is correct?

    Maths-General
    General
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    The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval open square brackets fraction numerator pi over denominator 6 end fraction comma fraction numerator 5 pi over denominator 6 end fraction close square bracketsis -

    The value of c in Lagrange’s theorem for the function f(x) = log sin x in the interval open square brackets fraction numerator pi over denominator 6 end fraction comma fraction numerator 5 pi over denominator 6 end fraction close square bracketsis -

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    General
    physics

    The relation between time and displacement of a moving particle is given by t equals 2 a x squaredwhere alpha is a constant. The shape of the graph  is x not stretchy rightwards arrow y is....

    The relation between time and displacement of a moving particle is given by t equals 2 a x squaredwhere alpha is a constant. The shape of the graph  is x not stretchy rightwards arrow y is....

    physicsGeneral
    General
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    If P (q) and Q open parentheses fraction numerator pi over denominator 2 end fraction plus theta close parentheses are two points on the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1, then locus of the mid – point of PQ is

    If P (q) and Q open parentheses fraction numerator pi over denominator 2 end fraction plus theta close parentheses are two points on the ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1, then locus of the mid – point of PQ is

    Maths-General
    General
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    If CP and CD are semi – conjugate diameters of an ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 comma then CP2 + CD2 =

    If CP and CD are semi – conjugate diameters of an ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1 comma then CP2 + CD2 =

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    parallel
    General
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    The normals to the curve x = a (theta + sin theta), y = a (1 – cos theta) at the points theta = (2n + 1) pi, n element of I are all -

    The normals to the curve x = a (theta + sin theta), y = a (1 – cos theta) at the points theta = (2n + 1) pi, n element of I are all -

    Maths-General
    General
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    The normal to the curve x = 3 cos theta – cos cubed theta, y = 3 sin theta – sin cubedtheta at the point theta = pi/4 passes through the point -

    The normal to the curve x = 3 cos theta – cos cubed theta, y = 3 sin theta – sin cubedtheta at the point theta = pi/4 passes through the point -

    Maths-General
    General
    Maths-

    The normal of the curve given by the equation x = a (sintheta + costheta), y = a (sintheta – costheta) at the point Q is -

    The normal of the curve given by the equation x = a (sintheta + costheta), y = a (sintheta – costheta) at the point Q is -

    Maths-General
    parallel
    General
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    If the tangent at ‘t’ on the curve y = 8 t cubed space minus 1, x = 4 t squared space plus space 3 meets the curve again at t subscript 1 and is normal to the curve at that point, then value of t must be -

    If the tangent at ‘t’ on the curve y = 8 t cubed space minus 1, x = 4 t squared space plus space 3 meets the curve again at t subscript 1 and is normal to the curve at that point, then value of t must be -

    Maths-General
    General
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    The tangent at (t, t squared – t cubed) on the curve y = x squared – x cubed meets the curve again at Q, then abscissa of Q must be -

    The tangent at (t, t squared – t cubed) on the curve y = x squared – x cubed meets the curve again at Q, then abscissa of Q must be -

    Maths-General
    General
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    If fraction numerator x over denominator a end fraction plus fraction numerator y over denominator b end fraction = 1 is a tangent to the curve x = 4t,y =fraction numerator 4 over denominator t end fraction, t element of R then -

    If fraction numerator x over denominator a end fraction plus fraction numerator y over denominator b end fraction = 1 is a tangent to the curve x = 4t,y =fraction numerator 4 over denominator t end fraction, t element of R then -

    Maths-General
    parallel
    General
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    The line fraction numerator x over denominator a end fraction + fraction numerator y over denominator b end fraction = 1 touches the curve  y space equals space b e to the power of negative x over a end exponent at the point :

    The line fraction numerator x over denominator a end fraction + fraction numerator y over denominator b end fraction = 1 touches the curve  y space equals space b e to the power of negative x over a end exponent at the point :

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    General
    physics

    An object moves in a straight line. It starts from the rest and its acceleration is . 2 ms2.After reaching a certain point it comes back to the original point. In this movement its acceleration  is -3 ms2, till it comes to rest. The total time taken for the movement is 5 second. Calculate the maximum velocity.

    An object moves in a straight line. It starts from the rest and its acceleration is . 2 ms2.After reaching a certain point it comes back to the original point. In this movement its acceleration  is -3 ms2, till it comes to rest. The total time taken for the movement is 5 second. Calculate the maximum velocity.

    physicsGeneral
    General
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    For the ellipse fraction numerator x to the power of 2 end exponent over denominator 2 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 1 end fraction equals 1 comma the foci are

    For the ellipse fraction numerator x to the power of 2 end exponent over denominator 2 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 1 end fraction equals 1 comma the foci are

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