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Maths-

General

Easy

Question

How many liters of a $25 straight percent sign$ saline solution must be added to 3 liters of a $10 straight percent sign$ saline solution to obtain a $15 straight percent sign$ saline solution?

hint Hint:

Hint:

Percentage is the number or ratio expressed as a fraction of 100 .

The correct answer is: Hence, 1.5 the liter we have to add to make the final solution15% of saline.

Explanation:

We have 3 a liter of $10 straight percent sign$ saline solution.

We have to find how many liters of a $25 straight percent sign$ saline solution must be added to 3 liters of a $10 straight percent sign$ saline solution to obtain a $15 straight percent sign$ saline solution.

Step 1 of 1:
Let the volume require of a $25 straight percent sign$ saline solution be x
And 3 liter will be added of a $10 straight percent sign$ solution
Now the total volume become $x plus 3$
So, According to the question after mixing we get
$25 straight percent sign left parenthesis x right parenthesis plus 10 straight percent sign left parenthesis 3 right parenthesis equals 15 straight percent sign left parenthesis x plus 3 right parenthesis$
On further calculation
$0.25 x plus 0.3 equals 0.15 left parenthesis x plus 3 right parenthesis$
$0.25 x plus 0.3 equals 0.15 x plus 0.45$
$0.1 x equals 0.15$
$x equals 1.5$
Hence, $1.5$ the liter we have to add to make the final solution $15 straight percent sign$ of saline.

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