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Maths-

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Question

If $0 less than theta comma ϕ less than pi divided by 2 text and end text x equals sum from n equals 0 to straight infinity of sin to the power of 2 n end exponent invisible function application theta comma y equals sum from n equals 0 to straight infinity of cos to the power of 2 n end exponent invisible function application ϕ subscript text and end text end subscript straight z equals sum from n equals 0 to straight infinity of cos to the power of straight n invisible function application left parenthesis theta plus ϕ right parenthesis cos to the power of straight n invisible function application left parenthesis theta minus ϕ right parenthesis$ then

xyz+1=yz-2x
xyz-1=yz+zx
xyz-xy=yz-2x
xyz+1=yz+zx

The correct answer is: xyz-xy=yz-2x

Related Questions to study

if $2 tan space A plus c o t space A equals tan space B$ then $c o t space A plus 2 tan space left parenthesis A minus B right parenthesis equals$

if $2 tan space A plus c o t space A equals tan space B$ then $c o t space A plus 2 tan space left parenthesis A minus B right parenthesis equals$

$text If end text fraction numerator cos begin display style text end text end style A over denominator cos begin display style text end text end style B end fraction equals n text and end text fraction numerator sin begin display style text end text end style A over denominator sin begin display style text end text end style B end fraction equals m text then end text open parentheses m squared minus n squared close parentheses sin squared text end text B equals$

$text If end text fraction numerator cos begin display style text end text end style A over denominator cos begin display style text end text end style B end fraction equals n text and end text fraction numerator sin begin display style text end text end style A over denominator sin begin display style text end text end style B end fraction equals m text then end text open parentheses m squared minus n squared close parentheses sin squared text end text B equals$

Find the projection of the vector $a with rightwards arrow on top equals 2 i with hat on top plus 3 j with hat on top plus 2 k with hat on top$ on the vector $stack b with rightwards arrow on top equals$ $i with ˆ on top plus 2 j with ˆ on top plus k with ˆ on top.$

Find the projection of the vector $a with rightwards arrow on top equals 2 i with hat on top plus 3 j with hat on top plus 2 k with hat on top$ on the vector $stack b with rightwards arrow on top equals$ $i with ˆ on top plus 2 j with ˆ on top plus k with ˆ on top.$

parallel

Let $stack a with ‾ on top equals 2 stack i with ˆ on top plus 3 stack j with ˆ on top minus 6 stack k with ˆ on top comma stack b with rightwards arrow on top equals 2 stack i with ˆ on top minus 3 stack j with ˆ on top plus 6 stack k with ˆ on top$ and $stack c with ‾ on top equals negative 2 stack i with ˆ on top plus 3 stack j with ˆ on top plus 6 stack k with ˆ on top times$ let $stack a with rightwards arrow on top subscript 1 end subscript$ be projection of $stack a with rightwards arrow on top$ on $stack b with rightwards arrow on top$ and $stack a with rightwards arrow on top subscript 2 end subscript$ be the projection of $stack a with rightwards arrow on top subscript 1 end subscript$ on $stack c with rightwards arrow on top$ . Then $stack a with rightwards arrow on top subscript 2 end subscript equals$

Let $stack a with ‾ on top equals 2 stack i with ˆ on top plus 3 stack j with ˆ on top minus 6 stack k with ˆ on top comma stack b with rightwards arrow on top equals 2 stack i with ˆ on top minus 3 stack j with ˆ on top plus 6 stack k with ˆ on top$ and $stack c with ‾ on top equals negative 2 stack i with ˆ on top plus 3 stack j with ˆ on top plus 6 stack k with ˆ on top times$ let $stack a with rightwards arrow on top subscript 1 end subscript$ be projection of $stack a with rightwards arrow on top$ on $stack b with rightwards arrow on top$ and $stack a with rightwards arrow on top subscript 2 end subscript$ be the projection of $stack a with rightwards arrow on top subscript 1 end subscript$ on $stack c with rightwards arrow on top$ . Then $stack a with rightwards arrow on top subscript 2 end subscript equals$

$text If end text sin text end text A plus sin space B equals square root of 3 left parenthesis cos space B minus cos space A right parenthesis$ then $sin space 3 A plus sin space 3 B equals$

$text If end text sin text end text A plus sin space B equals square root of 3 left parenthesis cos space B minus cos space A right parenthesis$ then $sin space 3 A plus sin space 3 B equals$

$s i n squared space alpha plus c o s squared space left parenthesis alpha plus beta right parenthesis plus 2 s i n space alpha s i n space beta c o s space left parenthesis alpha plus beta right parenthesis equals$

$s i n squared space alpha plus c o s squared space left parenthesis alpha plus beta right parenthesis plus 2 s i n space alpha s i n space beta c o s space left parenthesis alpha plus beta right parenthesis equals$

parallel

$text If end text sin text end text x cos space y equals 1 fourth$ and $3 tan space x equals 4 tan space y$ then $sin space left parenthesis x minus y right parenthesis equals$

$text If end text sin text end text x cos space y equals 1 fourth$ and $3 tan space x equals 4 tan space y$ then $sin space left parenthesis x minus y right parenthesis equals$

$c o t space A c o t space B equals 2 comma cos space left parenthesis A plus B right parenthesis equals 3 divided by 5 rightwards double arrow sin space A sin space B equals$

$c o t space A c o t space B equals 2 comma cos space left parenthesis A plus B right parenthesis equals 3 divided by 5 rightwards double arrow sin space A sin space B equals$

$text If end text x cos space theta equals y cos space open parentheses theta plus fraction numerator 2 pi over denominator 3 end fraction close parentheses equals z cos space open parentheses theta plus fraction numerator 4 pi over denominator 3 end fraction close parentheses$ then the value of $1 over x plus 1 over y plus 1 over z equals$

$text If end text x cos space theta equals y cos space open parentheses theta plus fraction numerator 2 pi over denominator 3 end fraction close parentheses equals z cos space open parentheses theta plus fraction numerator 4 pi over denominator 3 end fraction close parentheses$ then the value of $1 over x plus 1 over y plus 1 over z equals$

parallel

$text If end text 0 less than alpha comma beta less than pi over 4 comma cos space left parenthesis alpha plus beta right parenthesis equals 4 over 5 comma sin space left parenthesis alpha minus beta right parenthesis equals 5 over 13 text then end text tan text end text 2 alpha equals$

$text If end text 0 less than alpha comma beta less than pi over 4 comma cos space left parenthesis alpha plus beta right parenthesis equals 4 over 5 comma sin space left parenthesis alpha minus beta right parenthesis equals 5 over 13 text then end text tan text end text 2 alpha equals$

if $tan space left parenthesis A minus B right parenthesis equals 7 divided by 24 comma tan space A equals 4 divided by 3$ where A, B acute, then A+B=

if $tan space left parenthesis A minus B right parenthesis equals 7 divided by 24 comma tan space A equals 4 divided by 3$ where A, B acute, then A+B=

$text If end text cos space A equals 5 over 13 comma tan space B equals fraction numerator negative 15 over denominator 8 end fraction comma negative 270 to the power of ring operator less than straight A less than 360 to the power of ring operator comma 90 to the power of ring operator less than straight B less than 180 to the power of ring operator$ , then the quadrant to which A+B belongs is

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parallel

In a $triangle A B C comma fraction numerator t a n invisible function application B over denominator t a n invisible function application C end fraction equals 2 over 3$ and $t a n invisible function application A t a n invisible function application B t a n invisible function application C equals 6$ then the value(s) satisfy the equation

In a $triangle A B C comma fraction numerator t a n invisible function application B over denominator t a n invisible function application C end fraction equals 2 over 3$ and $t a n invisible function application A t a n invisible function application B t a n invisible function application C equals 6$ then the value(s) satisfy the equation

$t a n space 40 to the power of ring operator plus t a n space 80 to the power of ring operator minus √ 3 t a n space 40 to the power of ring operator t a n space 80 to the power of ring operator equals$

$t a n space 40 to the power of ring operator plus t a n space 80 to the power of ring operator minus √ 3 t a n space 40 to the power of ring operator t a n space 80 to the power of ring operator equals$

$text If end text 0 less than theta less than pi over 2 text and end text 2 sin invisible function application theta equals square root of 3 cos space 10 to the power of ring operator plus sin space 10 to the power of ring operator text then end text theta equals$

$text If end text 0 less than theta less than pi over 2 text and end text 2 sin invisible function application theta equals square root of 3 cos space 10 to the power of ring operator plus sin space 10 to the power of ring operator text then end text theta equals$

parallel

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