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Maths-

General

Easy

Question

If ω≠1 be a Cube Roots of Unity and (1+ω²)ⁿ= (1+ω⁴)ⁿ, then the least positive value of n is

2
3
5
6

The correct answer is: 3

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If the cube roots of unity are 1,w,w², then the roots of the equation (x-1)³+8=0 are

If the cube roots of unity are 1,w,w², then the roots of the equation (x-1)³+8=0 are

If z=x+ i y is a variable complex number such that arg⁡( $open parentheses fraction numerator straight z minus 1 over denominator straight z plus 1 end fraction close parentheses equals straight pi over 4$ then

If z=x+ i y is a variable complex number such that arg⁡( $open parentheses fraction numerator straight z minus 1 over denominator straight z plus 1 end fraction close parentheses equals straight pi over 4$ then

parallel

If z₁,z₂ and z₃,z₄ are two pairs of conjugate complex numbers, then arg $arg invisible function application open parentheses z subscript 1 over z subscript u close parentheses plus arg invisible function application open parentheses z subscript 2 over z subscript 1 close parentheses$

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If 1,a₁,a₂⋯⋯_n-1 are n roots of unity, then the value of (1-a₁)(1-a₂)(1-a₃)…(1-a_n-1 )

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If Im $open parentheses fraction numerator z minus 1 over denominator 2 z plus 1 end fraction close parentheses equals negative 4$ then locus of z is

If Im $open parentheses fraction numerator z minus 1 over denominator 2 z plus 1 end fraction close parentheses equals negative 4$ then locus of z is

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If z²+z+1=0 where z is a complex number, then value of $open parentheses z plus 1 over z close parentheses squared plus open parentheses z squared plus 1 over z squared close parentheses squared plus open parentheses z cubed plus 1 over z cubed close parentheses squared plus midline horizontal ellipsis times times plus open parentheses z to the power of 6 plus 1 over z to the power of 6 close parentheses squared$ is [ ]

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Choose the synonym of tale

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If a=Cis⁡ α,b=Cis⁡ β c=Cis γ and $fraction numerator left parenthesis b plus c right parenthesis left parenthesis c plus a right parenthesis left parenthesis a plus b right parenthesis over denominator a b c end fraction equals$
$K cos invisible function application open parentheses fraction numerator alpha minus beta over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator beta minus gamma over denominator 2 end fraction close parentheses cos invisible function application open parentheses fraction numerator gamma minus alpha over denominator 2 end fraction close parentheses$ then K= (H.W)

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What is the meaning of the following idiom
A Knuckle sandwich.

The polynomial x⁶+4x⁵+3x⁴+2x³+x+1 is divisible by

The polynomial x⁶+4x⁵+3x⁴+2x³+x+1 is divisible by

parallel

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