Maths-
General
Easy

Question

In an equilateral triangle ABC,D  is a point on the side BC , such that BD equals 1 third BC . Prove that
9 AD squared equals 7 AB squared

The correct answer is: Hence proved


    Solution :-
    Aim  :- Prove that 9 A D squared equals 7 A B squared
    Hint :- let the side of equilateral triangle be x , then we get height of equilateral
    triangle as left parenthesis x square root of 3 right parenthesis divided by 2  .Now , Find length of DE and apply pythagoras theorem in
    Right angle triangle ADE to find length of AD in terms of AB.
    Explanation(proof ) :-
    In equilateral triangle all sides are equal
    Let , AB = BC =  CA  = x
    Given BD = ⅓ BC = x/3
    In equilateral triangle ,the altitudes and medians coincide
    so,AE is median also i.e E is midpoint of BC 
    BE = x/2
    From diagram ,DE = BE - BD equals x over 2 minus x over 3 equals x over 6
    We get height of equilateral triangle when side x isfraction numerator x square root of 3 over denominator 2 end fraction
    Applying pythagoras theorem on triangle ADE
    We get A D squared equals D E squared plus A E squared equals open parentheses x over 6 close parentheses squared plus open parentheses fraction numerator x square root of 3 over denominator 2 end fraction close parentheses squared
    ∣ A D squared equals x squared over 36 plus fraction numerator 3 x squared over denominator 4 end fraction equals fraction numerator 28 x squared over denominator 36 end fraction equals 7 over 0 x squared

    Substitute x by AB as x = AB
    A D squared equals 1 over 9 A B squared not stretchy rightwards double arrow 9 A D squared equals 7 A B squared
    Hence proved

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