Maths-
General
Easy
Question
In an Isosceles triangle ABC , AB = AC= 25 cm, BC = 14 cm. Calculate the altitude from A on BC?
Hint:
Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
The correct answer is: Hence, the altitude AD on BC is 24 cm.
Given AB = AC = 25 cm and BC = 14 cm
In this triangle altitude from A to BC is AD, we know that altitude in an isosceles triangle is also a median.
So, BD = CD = 14/2 = 7 cm
Applying Pythagoras theorem to △ADB
AB² = AD² + BD²
25² = AD² + 7²
AD² = 625 − 49
AD² = 576
AD = 24 cm
Final Answer:
Hence, the altitude AD on BC is 24 cm.
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