Maths-
General
Easy
Question
In the following system of linear equations, k is a constant and x and y are variables. For what value of k will the system of equations have no solution?
kx - 3y = 4
4x - 5y = 7
Hint:
1. An equation where no value can be substituted for the variable which will satisfy the equation i.e. for no value of x (or any other variable in the equation), would LHS equal RHS.
Hence, an equation where LHS ≠ RHS for any value of x has no solutions.
2. For Equations with No solutions:-
(a1/a2) = (b1/b2) ≠ (c1/c2)
The correct answer is: For k = 2.4, the given set of equations will have no solution
Step-by-step solution:-
From the given information, we have-
kx - 3y = 4 ….................................................. (Equation i)
4x - 5y = 7 ….................................................. (Equation ii)
Comparing the above equations with standard form of equations i.e. ax + by = c, we get-
a1 = k, b1 = -3, c1 = 4
a2 = 4, b2 = -5, c2 = 7
We know that for Equations with no solution-
(a1/a2) = (b1/b2) ≠ (c1/c2)
i.e. k/4 = -3/-5 ≠ 4/7 .................................................. (Equation iii)
∴ k/4 = -3/-5 ........................................................................... (From Equation iii)
∴ k/4 = 3/5
∴ 5k = 4 * 3 .......................................................................... (Cross multiplying)
∴ 5k = 12
∴ k = 12/5
∴ k = 2.4
Final Answer:-
∴ For k = 2.4, the given set of equations will have no solution.
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