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Question

L t subscript left parenthesis x plus 0 right parenthesis left parenthesis left parenthesis 1 minus c o s invisible function application 2 x right parenthesis left parenthesis 3 plus c o s invisible function application x right parenthesis right parenthesis divided by left parenthesis x t a n invisible function application 4 x right parenthesis
is equal to

  1. 1
  2. 1 divided by 2
  3. 2
  4. 1 divided by 4

hintHint:

In this question first we will rearrange the equation by using formula cos open parentheses 2 x close parentheses equals 1 minus 2 sin squared open parentheses x close parentheses  and then we will use the standard limits to find the limit.
limit as x minus greater than 0 of fraction numerator tan open parentheses x close parentheses over denominator x end fraction equals 1 and limit as x minus greater than 0 of fraction numerator sin open parentheses x close parentheses over denominator x end fraction equals 1

The correct answer is: 2


    In this question we have to find the limit limit as x minus greater than 0 of fraction numerator left parenthesis 1 minus cos open parentheses 2 x close parentheses right parenthesis left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis over denominator x tan open parentheses 4 x close parentheses end fraction
    Step1: Using trigonometric formula and Standard limits
    We know that cos open parentheses 2 x close parentheses equals 1 minus 2 sin squared open parentheses x close parentheses  and limit as x minus greater than 0 of fraction numerator tan open parentheses x close parentheses over denominator x end fraction equals 1 and limit as x minus greater than 0 of fraction numerator sin open parentheses x close parentheses over denominator x end fraction equals 1
    limit as x minus greater than 0 of fraction numerator left parenthesis 1 minus left parenthesis 1 minus 2 sin squared open parentheses x close parentheses right parenthesis right parenthesis left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis over denominator x tan open parentheses 4 x close parentheses end fraction
    Step2: By Rearranging the equation.
    By multiplying both numerator and denominator by 4 x.
    limit as x minus greater than 0 of fraction numerator left parenthesis 1 minus 1 plus 2 sin squared open parentheses x close parentheses right parenthesis left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis over denominator x tan open parentheses 4 x close parentheses end fraction cross times fraction numerator 4 x over denominator 4 x end fraction
    => limit as x minus greater than 0 of fraction numerator left parenthesis 1 minus 1 plus 2 sin squared open parentheses x close parentheses right parenthesis left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis over denominator x cross times 4 x end fraction cross times fraction numerator 4 x over denominator tan open parentheses 4 x close parentheses end fraction
    => limit as x minus greater than 0 of fraction numerator left parenthesis 2 sin squared open parentheses x close parentheses right parenthesis left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis over denominator x cross times 4 x end fraction cross times fraction numerator 4 x over denominator tan open parentheses 4 x close parentheses end fraction
    => limit as x minus greater than 0 of fraction numerator left parenthesis 2 sin squared open parentheses x close parentheses right parenthesis over denominator 4 x squared end fraction cross times fraction numerator 4 x over denominator tan open parentheses 4 x close parentheses end fraction cross times left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis
    => limit as x minus greater than 0 of 1 half cross times open parentheses fraction numerator sin open parentheses x close parentheses over denominator x end fraction close parentheses squared cross times 1 cross times left parenthesis 3 plus cos open parentheses x close parentheses right parenthesis
    => 1 half cross times 1 cross times 4
    => 2

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