Maths-
General
Easy
Question
A friction clayton is in the form of the frustum of a cone, the diameters of the ends being 8cm, and 10cm and length 8cm Then its volume is
- 506.75 cm3
- 605.57 cm3
- 506.65 cm3
- 408.75 cm3
The correct answer is: 506.75 cm3
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